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3 years ago

Give the coordinates and quadrant of Point Z

Mathematics

1 answer:

Lorico [155]3 years ago

4 0

Answer:

(9,10) and Quadrant I

Step-by-step explanation:

I hope this helps you :)

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How do you find serface area

Romashka-Z-Leto [24]

Answer:

the formula for surface area is 2(lb + bh + lh) sq is that helps :))

Step-by-step explanation:

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3 years ago

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Which of the following number lines shows the correct sum of the number above and 4?

zheka24 [161]

Answer:

Step-by-step explanation:

because on you have to add 4 to the number above. so 3+4 equals 7 so you move 4 spaces to the right on the number line to get you 7. so C is the correct answer

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2 years ago

Y^2 - X when X = 6 and Y = 11

inn [45]

Answer:

Answer is below

Step-by-step explanation:

Evaluate for x=6,y=11

$11^2-6\\11^{2} -6\\=115$

So therefore your answer is 115

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4 years ago

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Help me with my math quiz from friday 4/1 <br> SHOW STEPS

malfutka [58]

Hie!! I will be solving the questions in the sequence of the attachments.

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4. As line SU and TV are intersecting each other at O.

A.T.Q, ∠UOV = (7x - 4)°

∠SOT = 87°

Then, ∠UOV = ∠SOT {Vertically Opposite Angles}

$\rightarrow\sf{7x - 4=87}$

$\rightarrow\sf{7x =87+4}$

$\rightarrow\sf{7x =91}$

$\rightarrow\sf{x =\frac{91}{7}}$

$\rightarrow\boxed{\bf{x =13}}$

_______________________________________

5. radius = 17ft

circumference of circle = 2πr

$\rightarrow\sf{circumference=2\times\frac{22}{7}\times17}$

$\rightarrow\boxed{\bf{circumference=106.8ft}}$

_______________________________________

3. ∠1 and ∠2 - add to 180 (linear pair)

∠1 and ∠3 - equal (Vertically Opposite Angles)

∠3 and ∠4 - add to 180 (linear pair)

∠2 and ∠4 - equal (Vertically Opposite Angles)

_______________________________________

2. 160° + (6x - 16)° = 180° (linear pair)

$\rightarrow\sf{6x - 16 = 180-160}$

$\rightarrow\sf{6x - 16 = 20}$

$\rightarrow\sf{6x = 20+16}$

$\rightarrow\sf{6x =36}$

$\rightarrow\sf{x =\frac{36}{6}}$

$\rightarrow\boxed{\bf{x =6}}$

8 0

2 years ago

CAN SOMEONE PLS ANSWER-If W(- 10, 4), X(- 3, - 1) , and Y(- 5, 11) classify AEXY by its sides . Show all work to justify your an

AnnZ [28]

Answer:

WX = $\sqrt{74} \approx 8.6023253\\\\$
XY = $2\sqrt{37} \approx 12.1655251\\\\$
WY = $\sqrt{74} \approx 8.6023253\\\\$
Classify: Isosceles

============================================================

Explanation:

Apply the distance formula to find the length of segment WX

W = (x1,y1) = (-10,4)

X = (x2,y2) = (-3, -1)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-3))^2 + (4-(-1))^2}\\\\d = \sqrt{(-10+3)^2 + (4+1)^2}\\\\d = \sqrt{(-7)^2 + (5)^2}\\\\d = \sqrt{49 + 25}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\$

Segment WX is exactly $\sqrt{74}$ units long which approximates to roughly 8.6023253

-------------------

Now let's find the length of segment XY

X = (x1,y1) = (-3, -1)

Y = (x2,y2) = (-5, 11)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-3-(-5))^2 + (-1-11)^2}\\\\d = \sqrt{(-3+5)^2 + (-1-11)^2}\\\\d = \sqrt{(2)^2 + (-12)^2}\\\\d = \sqrt{4 + 144}\\\\d = \sqrt{148}\\\\d = \sqrt{4*37}\\\\d = \sqrt{4}*\sqrt{37}\\\\d = 2\sqrt{37}\\\\d \approx 12.1655251\\\\$

Segment XY is exactly $2\sqrt{37}$ units long which approximates to 12.1655251

-------------------

Lastly, let's find the length of segment WY

W = (x1,y1) = (-10,4)

Y = (x2,y2) = (-5, 11)

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-5))^2 + (4-11)^2}\\\\d = \sqrt{(-10+5)^2 + (4-11)^2}\\\\d = \sqrt{(-5)^2 + (-7)^2}\\\\d = \sqrt{25 + 49}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\$

We see that segment WY is the same length as WX.

Because we have exactly two sides of the same length, this means triangle WXY is isosceles.

8 0

3 years ago