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Alik [6]
3 years ago
9

Which system is equivalent to 3x squared - 4y squared = 25 over -6x squared -2y squared = 11

Mathematics
1 answer:
TEA [102]3 years ago
3 0
So we are given the following system:
3x^2-4y^2=25\\
-6x^2-2y^2=11\\\text{Multiply the second equation by -2:}\\12x^2+4y^2=-22\\\text{Add to the first equation we get:}\\15x^2=3
\text{ therefore }x=\pm \sqrt{ \frac{1}{5} }
Using the first equation again we get:
3x^2-4y^2=25\\
3x^2=4y^2+25\\
x^2= \frac{1}{3}(4y^2+25)\\x^2= \frac{1}{3}(4 \frac{1}{5} +25)\\= \frac{43}{5}\\x=\pm \sqrt{ \frac{43}{5} }
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Variables x and y are in direct proportion, and y = 12.5 when x = 25. If x = 40, then y =
BabaBlast [244]
25/12.5 = 40/y
cross multiply
(25)(y) = (12.5)(40)
25y = 500
y = 500/25
y = 20 <====
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Step-by-step explanation:

Learning preference that Angela prefer is interpersonal. As it is defined as the interaction which done within one close group where member interact and share ideas among each other.

while intrapersonal refer to the oneself communications, visual and auditory communication used some video lesson and audio guide respectively to enhance one knowledge

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SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

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3 years ago
How to solve the formula for Vf in the formula of acceleration?
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Multiply by t on both sides to clear the denominator
at = Vf - Vi
Add Vi to both sides.
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