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lawyer [7]
3 years ago
14

(4x^5+3x^2-6)+(2x^5+3x^2+1)

Mathematics
2 answers:
Juliette [100K]3 years ago
8 0
Answer : 6x^5 + 6x^2 - 5

Combine the like terms :
4x^5 + 2x^5 = 6x^5
3x^2 + 3x^2 = 6x^2
-6 + 1 = -5

Put into descending order.
NeTakaya3 years ago
7 0

Answer:

6x^5+6x^2-5

Step-by-step explanation:

4x^5+2x^5=6x^5

3x^2+3x^2=6x^2

-6+1=5

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The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

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Find the integration of 16-x^{2}.

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