The coordinates of the endpoints of line segments T'V' are; T'(-1, 2) and V'(0, 1).
<h3>What are the coordinates of the endpoints of the segment T'V'?</h3>
It follows from the task content that the transformation involved in the formation of the image from the pre-image is dilation by a scale factor of 1/4.
On this note, given that the coordinates of T and V from the task content are; (-4, 8) and (0,4), it follows that the coordinates of the endpoints as required are; T'(-1, 2) and V'(0, 1).
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Answer:
$6.6
Step-by-step explanation:
you want to find out what 40% of the original price is ($11)
100% = 11
10%= 1.1
to get 40% you times it by 4
40%= 4.4
you then have to take away the sale reduction from the original
11- 4.4 =$6.6
I think the answer shouls be 80. But its not given in the options.
Complete Question
The complete question is shown on the first uploaded image
Answer:
1

2

3

4

Step-by-step explanation:
Generally the area of a sector is mathematically represented as

Now at
and 


Now at
in and 


Now at
and 


Now at
and 

