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3 years ago

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Please omg I really need help

1 answer:

lisabon 2012 [21]3 years ago

7 0

The answer would be C. Median.

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8 1/2 x 4/11 please solve

irakobra [83]

Answer:

3 1/11

Step-by-step explanation:

8 1/2 x 4/11

Change to an improper fraction

(2*8+1)/2 * 4/11

17/2 * 4/11

68 /22

Divide the top and bottom by 2

34/11

Change back to a mixed number

11 goes into 34 3 times with 1 left over

3 1/11

7 0

2 years ago

Read 2 more answers

6x+18=h(3x+9) what value the constant h in the equation shown below will result in a infinite number of solutions

pav-90 [236]

For there to be an infinite number of solutions, the quantity on the left side of the equation must be the same as on the right.
First, distribute the equation to get
6x + 18 = 3xh + 9h
If h = 2, the equation on the right would also be 6x + 18 which would yield the same equation and hence an infinite number of solutions
So the answer is h = 2

4 0

2 years ago

Read 2 more answers

Find the length of a B leave your answers in the terms of pi

algol [13]

Answer:

AB = 6*120*pi/180 = 4pi

8 0

2 years ago

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

3 years ago

A company claims that less than 10% of adults own a smart watch. You want to test this claim, and you find that in a random samp

Nezavi [6.7K]

Answer:

Test statistic is 0.67

Critical value is -2.33

Step-by-step explanation:

Consider the provided information.

The formula for testing a proportion is based on the z statistic.

$z=\frac{\hat p-p_0}{\sqrt{p_0\frac{1-p_0}{n}}}$

Were $\hat p$ is sample proportion.

$p_0$ hypothesized proportion and n is the smaple space,

Random sample of 100 adults, 12% say that they own a smart watch.

A company claims that less than 10% of adults own a smart watch.

Therefore, n = 100 $\hat p$ = 0.12 , $P_0$ = 0.10

$1 - P_0 = 1 - 0.10 = 0.90$

Substitute the respective values in the above formula.

$z=\frac{0.12-0.10}{\sqrt{0.10\frac{0.90}{100}}}$

$z\approx 0.67$

Hence, test statistic = 0.67

This is the left tailed test.

Now using the table the P value is:

P(z < 0.667) = 0.7476

P-value = 0.7476

$\alpha = 0.01$

Here, P-value > α therefore, we are fail to reject the null hypothesis.

$Z_{\alpha}= Z_{0.01} = -2.33$

Hence, Critical value is -2.33

7 0

3 years ago