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Flauer [41]
3 years ago
13

Please omg I really need help

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0
The answer would be C. Median.
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What kind of shape is this? O A. Not a polygon O B. Triangle O c. Quadrilateral O D. Pentagon​
Sophie [7]

Answer:

Add the picture please :) i will go on your page and answer when you add the image. Remember to always double check if you have the image clipped on whenever you ask something that needs an image, thank you.

6 0
3 years ago
Can anyone help me figure out how to do this
3241004551 [841]

Answer:

133m^2

Step-by-step explanation:

What if i say NO?

jk

3*3=9

8+3=11

12-3=9

sp

9*11=99

2 area coverd so far

99+9=108

7*2=14

108+14=122

Lastly the tir

10-7=3

11-3-2=6

6*4=24

24/2=12

133m^2

8 0
2 years ago
Math can you please help me with this thank you!
padilas [110]
Tip: whenever y equals a number, the line is horizontal and the slope is 0. if the number equals x, the line will be vertical and there is no slope.
4 0
3 years ago
Divide 30 in a ratio of 3:2
Sergeeva-Olga [200]
Other\ method:\\\\x;y-searches\\\\  \left\{\begin{array}{ccc}x+y=30&|subtract\ y\ from\ both\ sides\\x:y=3:2\end{array}\right\\\left\{\begin{array}{ccc}x=30-y&(1)\\\frac{x}{y}=\frac{3}{2}&(2)\end{array}\right\\\\subtitute\ (1)\ to\ (2):\\\\\frac{30-y}{y}=\frac{3}{2}\ \ \ \ |cross\ multiply\\\\(3)(y)=(2)(30-y)\\3y=60-2y\ \ \ \ |add\ 2y\ to\ both\ sides\\5y=60\ \ \ \ |divide\ both\ sides\ by\ 5\\\boxed{y=12}

Put\ the\ value\ of\ y\ to\ (1):\\x=30-12\\\boxed{x=18}\\\\Answer:\boxed{\left\{\begin{array}{ccc}x=18\\y=12\end{array}\right\to18:12}
4 0
3 years ago
Read 2 more answers
How to find the correct unit of measurement? I am struggling with this. What is the difference between ft³, ft and ft²? Example:
arlik [135]
<span> </span> <span>if you want to determine the perimeter / length, use a normal measure - ft.
The area is ft^{2}
<span>and the volume</span></span> ft^{3}
4 0
3 years ago
Read 2 more answers
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