1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kazeer [188]
3 years ago
9

(x + 1)/(3x + 9) * (x ^ 2 + 5x + 6)/(x - 2) Simplify your answer as much as possible .

Mathematics
1 answer:
IRISSAK [1]3 years ago
4 0

Answer:

(x^3 + 6x^2 + 11x + 6)/(3(x-2)(x+3))

Step-by-step explanation:

(x + 1)/(3x + 9) * (x ^ 2 + 5x + 6)/(x - 2)

(x^3 +5x^2 +6x +x^2 + 5x + 6)/(3x^2 - 6x + 9x -18)

(x^3 + 6x^2 + 11x + 6)/(3x^2 + 3x - 18)

(x^3 + 6x^2 + 11x + 6)/(3(x-2)(x+3))

You might be interested in
Given the picture below, find x and both angles.
Lisa [10]

Answer:

x =42.5

x+8 =50.5

3x+2 =  129.5

Step-by-step explanation:

The two angles shown are supplementary, so they add to 180

x+8   + 3x+2 = 180

Combine like terms

4x+10 = 180

Subtract 10

4x = 170

Divide by 4

x =42.5

x+8 = 42.5+8 = 50.5

3x+2 = 3*42.5 +2 = 127.5 +2 = 129.5

4 0
3 years ago
Read 2 more answers
90% of 250 please help ​
Anna007 [38]
I agree the answer is 225 and you can also use the calculator too.
6 0
3 years ago
Solve using elimination<br> x+y-2z=8<br> 5x-3y+z=-6<br> -2x-y+4z=-13
Free_Kalibri [48]
So here is your answer with LaTeX issued format interpretation. Full process elucidated briefly, below:

\begin{alignedat}{3}x + y - 2z = 8 \\ 5x - 3y + 2 = - 6 \\ - 2x - y + 4z = - 13 \end{alignedat}

For this equation to get obtained under the impression of those variables we have to eliminate them individually for moving further and simplifying the linear equation with three variables along the axis.

Multiply the equation of x + y - 2z = 8 by a number with a value of 5; Here this becomes; 5x + 5y - 10z = 40; So:

\begin{alignedat}{3}5x + 5y - 10z = 40 \\ 5x - 3y + z = - 6 \\ - 2x - y + 4z = - 13 \end{alignedat}

Pair up the equations in a way to eliminate the provided variable on our side, that is; "x":

5x - 3y + z = - 6

-

5x + 5y - 10z = 40
______________

- 8y + 11z = - 46

Therefore, we are getting.

\begin{alignedat}{3}5x + 5y - 10z = 40 \\ - 8y + 11z = - 46 \\ - 2x - y + 4z = - 13 \end{alignedat}

Multiply the equation of 5x + 5y - 10z = - 40 by a number with a value of 2; Here this becomes; 10x + 10y - 20z = 80.

Multiply the equation of - 2x - y + 4z = - 13 by a number with a value of 5; Here this becomes; - 10x - 5y + 20z = - 65; So:

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 8y + 11z = - 46 \\ - 10x - 5y + 20z = - 65 \end{alignedat}

Pair up the equations in a way to eliminate the provided variables on our side, that is; "x" and "z":

- 10x - 5y + 20z = - 65

+
10x + 10y - 20z = 80
__________________

5y = 15

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 8y + 11z = - 46 \\ 5y = 15 \end{alignedat}

Multiply the equation of - 8y + 11z = - 46 by a number with a value of 5; Here this becomes; - 40y + 55z = - 230.

Multiply the equation of 5y = 15 by a number with a value of 8; Here this becomes; 40y = 120; So:

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 40y + 55z = - 690 \\ 40y = 120 \end{alignedat}

Pair up the equations in a way to eliminate the provided variables on our side, that is; "y":

40y = 120

+

- 40y + 55z = - 230
_________________

55z = - 110

\begin{alignedat}{3}10x + 10y - 20z = 80 \\ - 40y + 55z = - 230 \\ 55z = - 110 \end{alignedat}

Solving for the variable of 'z':

\mathsf{55z = - 110}

\bf{\dfrac{55z}{55} = \dfrac{-110}{55}}

Cancel out the common factor acquired on the numerator and denominator, that is, "55":

z = - \dfrac{\overbrace{\sout{110}}^{2}}{\underbrace{\sout{55}}_{1}}

\boxed{\mathbf{z = - 2}}

Solving for variable "y":

\mathbf{\therefore \quad - 40y - 55 \big(- 2 \big) = - 230}

\mathbf{- 40y - 55 \times 2 = - 230}

\mathbf{- 40y - 110 = - 230}

\mathbf{- 40y - 110 + 110 = - 230 + 110}

Adding the numbered value as 110 into this equation (in previous step).

\mathbf{- 40y = - 120}

Divide by - 40.

\mathbf{\dfrac{- 40y}{- 40} = \dfrac{- 120}{- 40}}

\mathbf{y = \dfrac{- 120}{- 40}}

\boxed{\mathbf{y = 3}}

Solve for variable "x":

\mathbf{10x + 10y - 20z = 80}

\mathbf{Since, \: z = - 2; \quad y = 3}

\mathbf{10x + 10 \times 3 - 20 \times (- 2) = 80}

\mathbf{10x + 10 \times 3 + 20 \times 2 = 80}

\mathbf{10x + 30 + 20 \times 2 = 80}

\mathbf{10x + 30 + 40 = 80}

\mathbf{10x + 70 = 80}

\mathbf{10x + 70 - 70 = 80 - 70}

\mathbf{10x = 10}

Divide by this numbered value \mathbf{10} to get the final value for the variable "x".

\mathbf{\dfrac{10x}{10} = \dfrac{10}{10}}

The numbered values in the numerator and the denominator are the same, on both the sides. This will mean the "x" variable will be left on the left hand side and numbered values "10" will give a product of "1" after the division is done. On the right hand side the numbered values get divided to obtain the final solution for final system of equation for variable "x" as "1".

\boxed{\mathbf{x = 1}}

Final solutions for the respective variables in the form of " (x, y, z) " is:

\boxed{\mathbf{\underline{\Bigg(1, \: \: 3, \: \: - 2 \Bigg)}}}

Hope it helps.
8 0
3 years ago
Read 2 more answers
Item 16 A sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. What is the difference of the vol
Zigmanuir [339]

Answer:

672\pi \text{ cm}^3.

Step-by-step explanation:

We have been given that a sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. We are asked to find the difference of the volumes of the spheres.      

We will use volume formula of sphere to solve our given problem.

\text{Volume of sphere}=\frac{4}{3}\pi r^3, where r is radius of sphere.

The difference of volumes would be volume of larger sphere minus volume of smaller sphere.

\text{Difference of volumes}=\frac{4}{3}\pi(\text{8 cm})^3-\frac{4}{3}\pi(\text{2 cm})^3

\text{Difference of volumes}=\frac{4}{3}\pi(512)\text{ cm}^3-\frac{4}{3}\pi(8)\text{ cm}^3

\text{Difference of volumes}=\frac{4}{3}\pi(512-8)\text{ cm}^3

\text{Difference of volumes}=4\pi(168)\text{ cm}^3

\text{Difference of volumes}=672\pi\text{ cm}^3

Therefore, the difference between volumes of the spheres is 672\pi \text{ cm}^3.

3 0
4 years ago
Pleasee help with this question, or explain how to solve
krek1111 [17]

Answer:

The missing measure is 70.

Step-by-step explanation:

Because the two inside angles that arent next to each other on the suppelment add up to the outside angle, 120-50 is the missing angle. Sorry if this explaination is confusing.  

5 0
3 years ago
Other questions:
  • AB and BC form a right angle at point B. If A= (-3,-1) and B= (4,4) what is the equation of BC
    5·1 answer
  • (3) An estate was to be divided among five people. The first person received 1/8 of the estate. The next two people each receive
    7·1 answer
  • Which data set represents the histogram?
    12·1 answer
  • What is the tip for a bill that costs $80.50 at a 15% tip rate?
    12·1 answer
  • Tahmar knows the formula for simple interest is I = Prt, where I represents the simple interest on an amount of money, P, for t
    10·1 answer
  • Helpppp thank youuuu
    12·2 answers
  • Find dy/dx for y - xy + 1 = x-1
    5·1 answer
  • Plz help this paper is worth 50 points
    12·2 answers
  • Ava has 15 apples she gave 2 a way then got 3 apples back what is 15 - 2 + 3 = ?
    8·1 answer
  • Anybody Know This. ?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!