Answer:
Step-by-step explanation:
1. Null hypothesis: u <= 0.784
Alternative hypothesis: u > 0.784
2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation
Using the formula
sd = √[{P (1-P)}/n]
Where P = 0.84 and n = 750
sd =√[{0.84( 1- 0.84)/750]}
sd=√(0.84 (0.16) /750)
SD =√(0.1344/750)
sd = √0.0001792
sd = 0.013
Then using this we can find z
z = (p - P) / sd
z = (0.84-0.784) / 0.013
z =(0.056/0.013)
z = 4.3077
3. Find the p value and use it to make conclusions...
The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.
4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.
Answer:5m/2
Step-by-step explanation:
3m-m/2
(2×3m-1×m)/2
(6m-m)/2=5m/2
<span>The answer should be (12x + 20) (2x + 5)</span>
Answer:
Step-by-step explanation:
<u>Given function:</u>
The base of the exponent is 0.92. This represents a decay as 0.92 is less than 1. It would be a growth function is the base was greater than 1.
<u>The rate of decrease is </u>
<u>Percent decrease is </u>
A data point that is insignificantly larger or smaller than other values. for example...
2 3 6 1 129, 129 is an outlier because it is insignificantly larger than the others