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Lelechka [254]
4 years ago
15

If h(x) = 5 + x and k(X) =. 1/x which expression is equivalent to (kon)(x)?

Mathematics
2 answers:
VladimirAG [237]4 years ago
8 0

Answer:

(5+x)/x

Step-by-step explanation:

Given

h(x)= 5+x

k(x)= 1/x

(koh)(x)=?

Here you multiply

1/x( 5+x)

5/x +x/x

5/x+1 or

5/x +x/x

(5+x)/x

Doss [256]4 years ago
6 0

For this case we have the following functions:

h (x) = 5 + x\\k (x) = \frac {1} {x}

We must find (k_ {0} h) (x):

By definition of compound functions we have to:

(k_ {0} h) (x) = k (h (x)

So:

k (h (x) = \frac {1} {5 + x}

Finally:

(k_ {0} h) (x) = \frac {1} {5 + x}

Answer:

(k_ {0} h) (x) = \frac {1} {5 + x}

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