Answer:
127/12
Step-by-step explanation:
4 × 2 + 12x = 135
(1. Simplify 4 x 2 to 8.
8 + 12x = 135
(2. Subtract 88 from both sides.
12x= 135 - 8
(3. Simplify 135 - 8 to 127
12x = 127
(4. Divide both sides by 12
x= 127/12
Decimal Form: 10.583333
I think this is the awnser, but don't quote me on that
You need to give us the diagram
What are you supposed to do
Because he was born February 29.......
It comes once in four years so ..his age will be 15
![\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$3500\\ r=rate\to 6\%\to \frac{6}{100}\to &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\to &4\\ t=years\to &12 \end{cases} \\\\\\ A=3500\left(1+\frac{0.06}{4}\right)^{4\cdot 12}\implies A=3500(1.015)^{48}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BCompound%20Interest%20Earned%20Amount%7D%0A%5C%5C%5C%5C%0AA%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%0A%5Cquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%20%26%5C%243500%5C%5C%0Ar%3Drate%5Cto%206%5C%25%5Cto%20%5Cfrac%7B6%7D%7B100%7D%5Cto%20%260.06%5C%5C%0An%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%0A%5Ctextit%7Bquarterly%2C%20thus%20four%7D%0A%5Cend%7Barray%7D%5Cto%20%264%5C%5C%0At%3Dyears%5Cto%20%2612%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D3500%5Cleft%281%2B%5Cfrac%7B0.06%7D%7B4%7D%5Cright%29%5E%7B4%5Ccdot%2012%7D%5Cimplies%20A%3D3500%281.015%29%5E%7B48%7D)
so, the interest earned then will be A - 3500.