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OLga [1]
3 years ago
11

A hemisphericical tank is filled with water and has a diameter of 13 feet.if water weighs 62.4 ponds per cubic foot,what is the

total weight of the water ima full tank to the nearest pound?
Mathematics
1 answer:
Sindrei [870]3 years ago
7 0

The weight of the water in the tank is 35904.96 pounds.

Step-by-step explanation:

Given,

The diameter of the hemispherical tank is 13 ft

So, the radius = 6.5 ft

The water weighs 62.4 pounds

To find the weight of the water in the tank we need to find the volume of the tank first.

Formula

The volume of the tank = \frac{2}{3}πr^{3} sq ft

So, the volume of the tank is = \frac{2}{3}π6.5^{3} cube ft

= 575.40 cube ft

So,

The weight of the water = 575.40×62.4 pounds (approx)

= 35904.96 cube ft

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Answer:

Basic parabola:  y = ax2 + bx + c

We have 3 points we can plug in for (x, y) to create 3 simultaneous equations

(-2, 24):  24 = 4a - 2b + c   {equation 1}

(3, -1):   -1 = 9a + 3b + c    {equation 2}

(-1, 15): 15 = a - b + c        {equation 3}

Solve this system to find the values of a, b, c

Let's first eliminate variable c:

4a - 2b + c = 24   {equation 1}

 a -  b + c = 15    {equation 3}

---------------------  subtract

3a - b = 9

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--------------------  subtract

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Multiply equation 4 through by 4 and add equations

12a - 4b = 36

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-----------------   add

20a = 30

a = 30/20

a = 3/2

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8(3/2) + 4b = -6

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b = -9/2

Plug these 2 values into one of the original equations and solve for c

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15 = 3/2 + 9/2 + c

15 = 12/2 + c

15 = 6 + c

c = 15-6

c = 9

y = (3/2)x2 - (9/2)x+ 9

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Step-by-step explanation:

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