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dedylja [7]
3 years ago
10

on a scale drawing, a tree is 6 3/4 inches tall. the scale factor is 1/20. find the height of the actual scale.

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0
6.0875 is the answer I think
Sholpan [36]3 years ago
3 0
20*6.75 inches is 135 inches or 11 feet and 3 inches.
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if i want the track to have a circumference of 400 feet what does the diameter of the track need to be?
natta225 [31]

Answer:

The diameter of the track needs to be 127.27 feet

Step-by-step explanation:

* Lets explain how to solve the problem

- The circumference of any circle is C = 2πr, where r is the radius

  of the circle and π is the constant ratio between the

  circumference and the diameter of the circle which

  approximately is 22/7 or 3.14

- The diameter of any circle is twice its radius

* <u><em>Lets solve the problem</em></u>

- The circumference of the track is 400 feet

∵ The circumference = 2πr

∵ π = 22/7

∴ 400 = 2 × 22/7 × r

∴ 400 = 44/7 r

- Divide both sides by 44/7 to find r

∴ r = 63.63

∵ The diameter of the circle = 2r

∵ The radius = 63.63 feet

∴ The diameter = 63.63 × 2 = 127.27 feet

* The diameter of the track needs to be 127.27 feet

6 0
3 years ago
Evaluate the expression 3x+2
scoray [572]

It's  3x+2 because 3 ÷2 is 6 so it's  3x+2

3 0
4 years ago
Adam traveled out of town for a regional basketball tournament. He drove at a steady speed of 72.4 miles per hour for 4.62 hours
AnnyKZ [126]

Answer:

Adam traveled a distance of about 335 miles

Step-by-step explanation:

72.4 * 4.62 = 334.488

334.488 rounds to 335.

Adam traveled a distance of about 335 miles.

Hope this helps you! (:

-Hamilton1757

4 0
3 years ago
Read 2 more answers
The same survey database cited in exercise 4.3.1 (A-5) shows that 32 percent of U.S. adults indicated that they have been tested
yawa3891 [41]

Answer:

a. P(X = 3) = 0.145736

b. P(5≤X≤9) = 0.5462

c. P(5<X<10) = 0.3332

d. P(X≥6) = 0.3393

e. P(X<5) = 0.4477

f. Mean = 4.8, Variance = 3.264

Step-by-step explanation:

Given - The same survey database cited in exercise 4.3.1 (A-5) shows

             that 32 percent of U.S. adults indicated that they have been

             tested for HIV at some point in their life. Consider a simple

             random sample of 15 adults selected at a time. Let X be the

             number of adults who have been tested for HIV in the sample.

To find - For the following, find the numerical answer and describe

              the answer in words:

              a. Three

              b. Between five and nine, inclusive

              c. More than five, but less than 10

              d. Six or more

              e. Less than five

              f. Find the mean and the variance of the number of people

                 tested for HIV in samples of size 15.

Proof -

Given that , n = 15, p = 32% = 0.32

Now,

a.

P(X = 3) = binomial distribution (3, 15, 0.32, 0)

             = \left(\begin{array}{ccc}15\\3\end{array}\right)(0.32)^{3}(1-0.32)^{15 - 3}

             = 455(0.032768)(0.009774)

             = 0.145736

⇒P(X = 3) = 0.145736

b.

P(5≤X≤9) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)

               = \left(\begin{array}{ccc}15\\5\end{array}\right)(0.32)^{5}(1-0.32)^{15 - 5}+ \left(\begin{array}{ccc}15\\6\end{array}\right)(0.32)^{6}(1-0.32)^{15 - 6} + \left(\begin{array}{ccc}15\\7\end{array}\right)(0.32)^{7}(1-0.32)^{15 - 7} + \left(\begin{array}{ccc}15\\8\end{array}\right)(0.32)^{8}(1-0.32)^{15 - 8}+ \left(\begin{array}{ccc}15\\9\end{array}\right)(0.32)^{9}(1-0.32)^{15 - 9}

               = 0.213 + 0.1671 + 0.1011 + 0.0476 + 0.0174

               = 0.5462

⇒P(5≤X≤9) = 0.5462

c.

P(5<X<10) = + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)

                 =  \left(\begin{array}{ccc}15\\6\end{array}\right)(0.32)^{6}(1-0.32)^{15 - 6} + \left(\begin{array}{ccc}15\\7\end{array}\right)(0.32)^{7}(1-0.32)^{15 - 7} + \left(\begin{array}{ccc}15\\8\end{array}\right)(0.32)^{8}(1-0.32)^{15 - 8}+ \left(\begin{array}{ccc}15\\9\end{array}\right)(0.32)^{9}(1-0.32)^{15 - 9}

               =  0.1671 + 0.1011 + 0.0476 + 0.0174

               = 0.3332

⇒P(5<X<10) = 0.3332

d.

P(X≥6) = 1 - P(X < 6)

           = 1 - P(X ≤ 5)

           = 1 - binomial(5, 15, 0.32, 1)

           = 1 - 0.6607

           = 0.3393

⇒P(X≥6) = 0.3393

e.

P(X<5) = P(X≤4)

           = binomial (4, 15, 0.32, 1)

           = 0.4477

⇒P(X<5) = 0.4477

f.

Mean = np

         = 15(0.32)

         = 4.8

⇒Mean = 4.8

Variance = np(1-p)

              = 15(0.32)(1 - 0.32)

              = 4.8(0.68)

              = 3.264

⇒Variance = 3.264

3 0
3 years ago
To install the right size heating and cooling syster, you must know how many cubic feet an office building contains. The buildin
Lyrx [107]

Answer:

Mizuki is here to help!

115200 ft^3 is the volume of the building.

Step-by-step explanation:

120 x 20 x 48 =

2400 x 48 =

115200

6 0
4 years ago
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