3 years ago

Write h(x) in general form h(x)=x(x-5)+5

Mathematics

1 answer:

bekas [8.4K]3 years ago

5 0

H(x)

x-5+dx=+5;5x-5(x)+5/h(x)-5x(5)+5

+ h = + 90 = 90° ay + k = 2(1) + 8 = 10+5(x)

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∠EFG and ∠GFH are a linear pair, m∠EFG=3n+23, and m∠GFH=2n+32. What are m∠EFG and m∠GFH?

NARA [144]

the measures of the angles are:

m∠EFG = 98°
m∠GFH = 82°

<h3>How to find the measures of the angles?</h3>

Two angles are a linear pair if their measures add up to 180°.

Then we will have that:

∠EFG + ∠GFH = 180

Here we know that:

m∠EFG=3n+23

m∠GFH=2n+32

Replacing that we get:

3n + 23 + 2n + 32 = 180

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5n = 180 - 55 = 125

n = 125/5 = 25

Then the measures of the angles are:

m∠EFG=3n+23 = 3*25 +23 = 98°

m∠GFH=2n+32 = 2*25 + 32 = 82°

If you want to learn more about angles:

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