Answer:
he cable car's elevation will be 750 feet after 15 minutes
Step-by-step explanation:
Given:
elevation, e =2,000 feet
rate, I = 50 feet/minute
The equation that models the car's elevation, e, after t minutes is e = |t
The cable car's elevation will be 750 feet after how many minutes?
since, e = It
for 2,000 feet = 50 feet/minute * t
t = 2000/50 =40minutes
using the same constant rate, I for 750ft, T =
since, e = It
for 750 feet = 50 feet/minute * t
t = 750/50 =15minutes
200,000,000 + 40,000,000 + 9,000,000 + 100,000 + 4,000 + 300 + 30
D = vt
Distance traveled by train
d = 55t
Distance traveled by plane
d = 285t
Total distance
d = 1020
So, you do:
distance traveled by plane + distance traveled by train = total distance
(55t) + (285t) = 1020
Solve for t
t = 3 hours
t is the time traveled by each so 3 hrs traveled by train and 3 hrs traveled by plane
Total time = 3 + 3 = 6 hours
