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dalvyx [7]
3 years ago
9

In ΔEFG, is it possible for segment GE to measure 4 units?

Mathematics
2 answers:
denis-greek [22]3 years ago
6 0

Answer:

No, because 3 + 5 > 4, 5 + 4 > 3, and 4 + 3 > 5

kiruha [24]3 years ago
6 0

Answer: <u><em>OPTION D:</em></u> Yes, because 3 + 5 > 4, 5 + 4 > 3, and 4 + 3 > 5.

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Which set of numbers is the most reasonable to describe the temperature in alaska during the winter?
Zielflug [23.3K]
The rational numbers are the positive counting numbers: 1, 2, 3, 4, . . .

The whole number are the natural numbers plus 0: 0, 1, 2, 3, . . .

The irrational numbers are the numbers which cannot be expressed in the form a/b where a and b are integers. They are usually in the form of a non recurring and non terminating decimals.

The integers complices of both the negative and the positive whole numbers.

In winter, the temperature of Alaska usually drop to negative numbers.

Therefore, the <span>set of numbers is the most reasonable to describe the temperature in alaska during the winter is the set of integers.</span>
5 0
3 years ago
Read 2 more answers
I need help with number 1
rjkz [21]

Answer:∠1=55° ∠2=55° ∠3=55° ∠4=70° ∠5=55°

Step-by-step explanation:

We know that opposite angles of rhombus are congruent and the diagonals of rhombus cut the vertex angles into half. So ∠4=70° and ∠2=∠3=∠1=∠5.

Let ∠2+∠3=x

the sum of four angles of rhombus= 360°

70+70+ x +x = 360°

140+2x = 360°

2x=220°

x=110°

∠2=110°/2=55°=∠3=∠1=∠5

3 0
3 years ago
1. Given GH = 7x + 3, HI= 3x - 5,<br> and GI= 9x + 5.<br> H<br> G<br> A. Find x:<br> B. Find GH:
blsea [12.9K]

Answer:

\boxed{\bf x=7}

\boxed{\bf GH= 52}

Step-by-step explanation:

In the line segment..

\bf 7x+3+3x-5=9x+5

Combine like terms.

  • \bf 10x-2=9x+5

Add -2 to both sides.

  • \bf 10x-2+2=9x+5+2
  • \bf 10x=9x+7

Subtract 9x from both sides.

  • \bf 10x-9x=9x+7-9x
  • \boxed{\bf x=7}

\bf GH=7x+3

  • \bf 7(7)+3
  • \bf 49+3
  • \boxed{\bf 52}
<h3>__________________</h3>
6 0
3 years ago
What’s the answer...........
strojnjashka [21]
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8 0
3 years ago
Evaluate the following trigonometric expression, using the principal value for the cosine
Maslowich

Given:

The expression is

\tan (\cos ^{-1}(-\dfrac{1}{2}))

To find:

The value of given expression.

Solution:

We have,

\tan (\cos ^{-1}(-\dfrac{1}{2}))

=\tan (\pi-\cos^{-1}(\dfrac{1}{2}))          [\because \cos^{-1}(-\theta)=\pi -\cos^{-1}\theta]

=\tan (\pi-\cos^{-1}(\cos \dfrac{\pi}{3}))      [\because \cos \dfrac{\pi}{3}=\dfrac{1}{2}]

=\tan (\pi-\dfrac{\pi}{3})

=-\tan (\dfrac{\pi}{3})                 [\because \tan(\pi-\theta)=-\tan \theta]

=-\sqrt{3}         [\because \tan \dfrac{\pi}{3}=\sqrt{3}]

Therefore, the value of given expression is -\sqrt{3}.

5 0
3 years ago
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