Lon: f(x) = 2x2 + 1 The answer?
1 answer:
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Answer:
If you have a general point (x, y), and you reflect it across the x-axis, the coordinates of the new point will be:
(x,-y)
So we only change the sign of the y-component.
Now, if we do a reflection across the x-axis of a whole figure, then we apply the reflection to all the points that make the figure.
Then, we could just apply the reflection to the vertices of the square, then graph the new vertices, and then connect them, that is equivalent to graph the image of the square after the reflection.
The original vertices are:
C = (-3, 7)
D = (0, 7)
E = (0, 10)
F = (-3, 10)
Now we apply the reflection, remember that this only changes the sign of the y-component, then the new vertices are:
C' = (-3, -7)
D' = (0, -7)
E' = (0, - 10)
F' = (0, - 10)
Now we need to graph these points and connect them to get the reflected figure, the image can be seen below.
<h3>Answer: B. (-1, 0)</h3>
This point is below both the red diagonal line and the blue parabola. We know that the set of solution points is below both due to the "less than" parts of each inequality sign.
In contrast, a point like (2,2) is above the parabola which is why it is not a solution. It does not make the inequality true. So this is why we can rule choice A out.
Choice C is not a solution because (4,1) does not make true. This point is not below the red diagonal line. We can cross choice C off the list.
Choice D is similar to choice A, which is why we can rule it out as well.