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Ber [7]
3 years ago
11

I have 3 circles that are divided by halves,

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0
For each halve it would be a full or for all of the halve together it would be 6/2
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Sammy solve 68 math problems in 17 minutes at what rate did he solve the math problems​
katen-ka-za [31]

Answer:

4 math problems/minute

Step-by-step explanation:

68/17

8 0
3 years ago
Read 2 more answers
In the pediatric unit of a hospital has 165 beds how many are there if each room holds 3 beds
andrew-mc [135]

Answer:

There are 55 rooms

Step-by-step explanation:

There are 165 beds in the hospital. Each room contains 3 beds. In order to find the number of beds per room, take the total number of beds and divide it by the number of rooms in each bed. 165/3=55. There are 55 rooms in the hospital, all containing 3 beds.

Hope this helps!

8 0
3 years ago
How to determine if set of vectors is linearly independent?
zimovet [89]
The vectors \{v_1,v_2,...,v_p\}\in \mathbb{R}^n are linearly independent if the ONLY solution to the following equation:

c_1v_1+c_2v_2+...c_pv_p=0

is c_1=c_2=...=c_p=0
7 0
3 years ago
Use substitution to solve the system of equations :
mote1985 [20]

Answer:

x=1

y=-4

Step-by-step explanation:

4x+y=0  ->    y= -4x

2(-4x)+x=-7

-8x+  x=-7

-7x=-7

x=-7/-7=1

y=-4 . 1 = -4

3 0
3 years ago
If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components a
sammy [17]
There is some inforrmation that is missing in this question. It should read:

<span><span>A container holds 50 electronic components, of which 10 are defective. If 6 components are drawn at random from the container, the probability that at least 4 are not defective is . If 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .

</span><u>Answers</u>
<span>Part 1.   0.02
Part 2.  </span></span>0.0375<span><span>

</span><u>Explanation</u>
The probability is a chance of an event happening. It is calculated as;
probability = (Number of favourable outcome)/(Number of available outcome)

Part 1
6 are chosen at random. If 4 are not defective, then 2 are defective.
P(at least 4 are not defective) = 4/40 </span>× 2/10
                                                = 1/10 ×1/5
                                                = 1/50
                                                 = 0.02

Part 2
8 are chosen at random. If 3 are defective, the 5 are not defective. 
P(3 are defective) = 3/40 × 5/10 
                             = 15/400
                             = 3/80
                            = 0.0375
4 0
3 years ago
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