Question

Find an equation for the line that passes through point (-2,4) and (4,-5) (Show Work)

Answer 1

Answer:

$\Huge\boxed{\mathsf{Y=-\frac{3}{2}x+1}}}$

Step-by-step explanation:

TO FIND:

The slope of (-2,4) and (4,-5).

TO SOLVE:

With slope-intercept form and slope formula.

SLOPE FORMULA:

$\displaystyle \mathsf{\Rightarrow \frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN} }}$

SLOPE-INTERCEPT FORM:

$\displaystyle \mathsf{\Rightarrow Y=MX+B}}$

SOLUTIONS:

Y₂=(-5)

Y₁=4

X₂=4

X₁(-2)

Solve.

$\displaystyle \mathsf{\frac{(-5)-4}{4-(-2)}=\frac{(-5)-4}{4+2}=\frac{-9\div3}{6\div3}=\frac{-3}{2}=-\Rightarrow \frac{3}{2} }}$

Y-intercept is 1.

Y=-3/2x+1.

$\Large\boxed{\mathsf{Y=-\frac{3}{2}x+1 }}}$

The correct answer is y=-3/2x+1.

Answer 2

Answer:

y=-9/6x+1

Step-by-step explanation:

Slope=y2-y1/x2-x1

1) Find the slope of the line:

(-5-4)/(4+2)

2) Simplify:

m= -9/6

3) Now plug in the slope into point slope formula: (attached as picture)

(y-4)=-9/6(x+2)

4) Distribute -9/6 to x and 2:

y-4=-9/6x-3

5) Add 4 to both sides:

y=-9/6x+1