Answer:
Jamar is correct.
Step-by-step explanation:
The scores are as follows :
−3, 2, 0, −1, 2, −4.
These numbers include negative, positive and 0 as well. These numbers cannot written in a fractional form. It means they are integers.
Here, amar says these numbers can all be described as integers, while Sophia says they are whole numbers.
It would mean that Amar is correct. Sophia is incorrect because she told that the are whole numbers. Whole numbers are simply number like 0,1,2,3,4....
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer:
<u>1728 in²</u>
Step-by-step explanation:
For the area of B, you need to find the length and width (height and base, whatever you want to call it).
For the height, you would need to do: 144 - 36 - 24 - 36 = <u>48 inches</u>
For the base, you would need to do: 60 - 24 = <u>36 inches</u>
Now you multiply the base and height to get the area: 48 x 36 = <u>1728 in²</u>
Start at 5 and go up 3 and move 4 to the right
