26.) 3(2)² - 8(-3)²
= 3*4 - 8 + 9
= 12 - 8 + 9 = 13
27.) I 7 - 4(2) I
7 - 8 = -1, but since this is absolute value, which is a number's distance from zero, your answer for 27 would be a positive one.
28.) (-2)² + 2(-3 * 1)
= 4 + 2(-3)
= 4 + (-6) = 4 - 6 = -2
29.) 7(-4)² + 5 / 4(1) - (-5)
=7 * 16 + 5 / 4 + 5
= 112 + 5 / 9 = 117/9 = 13
30.) Product: the result of a multiplication problem
Increased by: multiplied by
3(n * 7)
31.) 2n - 1
Using subtraction of perfect squares, it is found that the factored expression is:
9t² - 4 = (3t - 2)(3t + 2).
<h3>What is the subtraction of perfect squares factoring?</h3>
It is given as follows:
a^2 - b^2 = (a - b)(a + b)
In this problem, the binomial is given as follows:
9t² - 4.
Hence:
Hence the factored expression is:
9t² - 4 = (3t - 2)(3t + 2).
More can be learned about subtraction of perfect squares at brainly.com/question/16948935
#SPJ1
Answer:
x = 158
y = 22
Step-by-step explanation:
A triangle's inside sides sum up to 180 degrees. So to find the angle y, just take 180 - the sum of the other two sides.
70 + 88 = 158
180 - 158 = 22
y = 22 degrees
Now, to find angle x, since x and y are next to each other on a straight line, it means they are supplementary angles. Supplementary angles add together to equal 180, so just substract y from 180 to get x.
180 - 22 = 158
x = 158 degrees
Answer:
D
21√2/2
C
C
C
Step-by-step explanation:
For all problems, the ratios of the lengths of the sides are:
30-60-90 triangle 1 : √3 : 2
45-45-90 triangle 1 : √2 : √2
Problem 3:
30-60-90 triangle at left
Hypotenuse = 11
Short leg = 11/2
Long leg = 11/2 × √3
45-45-90 triangle at right
x = 11/2 × √3 × √2 = 11√6/2
Answer: D
Problem 4:
30-60-90 triangle at top
Hypotenuse = 7√3
Short leg = 7√3/2
Long leg = 7√3/2 × √3 = 7 × 3/2 = 21/2
45-45-90 triangle at right
x = 21/2 × √2 = 21√2/2
Answer: 21√2/2
Problem 7:
30-60-90 triangle
Long leg = 4√3
Short leg = y = 4√2/2 = 2√2
Answer: C.
Problem 6:
30-60-90 triangle at left
Hypotenuse = 12√6
Short leg = 12√6/2 = 6√6
Long leg = 6√6 × √3 = 6√2√3√3 = 18√2
45-45-90 triangle at right
x = 18√2/√2 = 18
Answer: C.
Problem 8:
45-45-90 triangle
Hypotenuse = 2
Leg = y = 2/√2 = 2√2/(√2√2) = √2
Answer: C.
Answer:
hope it helps
Step-by-step explanation::
a) Consider a body having initial velocity 'u'. Suppose it is subjected to a uniform acceleration 'a' so that after time 't' its final velocity becomes 'v'. Now, from the definition of acceleration we know that:
Acceleration = Time taken Change in velocity or Acceleration = time taken
Final velocity- Initial velocity
So, a= t
v−u
at=v−u and, v=u + at
where v= final velocity of the body
u= initial velocity of the body
a= acceleration
and t= time taken
(b) Initial velocity, u=54km/h=15m/s
Final velocity, v=0m/s
Time, t=8s
Acceleration, a=?
a= t
v−u
= 8
0−15
= 8
−15
m/s 2
=−1.875m/s 2
