Question

Find the distance of a(1,8) and point c (-8,-6) then find the midpoint of ac

Answer 1

$\text{MIdpoint =} \bigg(\dfrac{1 + (-8)}{2}, \dfrac{8+(-6)}{2} \bigg) = \bigg(\dfrac{-7}{2}\ , \ \dfrac{2}{2} \bigg) = \bigg(-3.5 \ , \ 1 \bigg)$

Answer: The midpoint (-3.5, 1)