The complement of an angle is 90 minus the angle, or
90 - x = complement angle
if x is 18 more than 3 times it's complement, then
x = 3(complement angle) + 18
We can substitute "90 - x" for the "complement angle" in the second equation:
x = 3(90 - x) + 18
distribute the 3 to the 90 and the x
x = 270 - 3x + 18
add 3x to both sides
4x = 270 - 18
4x = 252
x = 63
the measure of angle x is 63 degrees
Answer:
g(-4) = 3
Step-by-step explanation:
g(x) = -x - 1
g(-4) = -(-4) - 1
g(-4) = 4 - 1
g(-4) = 3
The rule for negative exponents is that if the exponent is negative to begin with, in order to make it negative, you put it into the denominator of a fraction, and raise it to whatever the power is. To go from positive exponents (those that are already in the denominator), move it up to the numerator and make the exponent negative. So your solution would be 5x^-2
Answer:
![a_5 = 32](https://tex.z-dn.net/?f=a_5%20%3D%2032)
Step-by-step explanation:
The nth term for the geometric sequence is given by:
![a_n = a_1 \cdot r^{n-1}](https://tex.z-dn.net/?f=a_n%20%3D%20a_1%20%5Ccdot%20r%5E%7Bn-1%7D)
where,
is the first term
r is the common ratio
n is the number of terms.
As per the statement:
For the geometric sequence of
and r=2
We have to find ![a_5](https://tex.z-dn.net/?f=a_5)
for n = 5;
![a_5=a_1 \cdot r^{n-1}](https://tex.z-dn.net/?f=a_5%3Da_1%20%5Ccdot%20r%5E%7Bn-1%7D)
Substitute the given values we have;
![a_5 = 2 \cdot 2^4 = 2 \cdot 16](https://tex.z-dn.net/?f=a_5%20%3D%202%20%5Ccdot%202%5E4%20%3D%202%20%5Ccdot%2016)
⇒![a_5 = 32](https://tex.z-dn.net/?f=a_5%20%3D%2032)
Therefore, the value of
is, 32
C), cause you would subtract 5 from 53 in order to move it, and would get 6x=48. Then, you would divide by six on both sides, and the answer would be x=8, so Number C.