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Taya2010 [7]
3 years ago
5

Assume that you select 2 coins at random from 8 coins: 5 dimes and 3 quarters.

Mathematics
1 answer:
Vilka [71]3 years ago
7 0
If the coins are selected without replacement, the probability of 2 dimes is:\frac{5}{8}\times\frac{4}{7}=\frac{5}{14}
The answer is 5/14.
Using the formula for a hypergeometric distribution, we get:
P(2\ dimes)=\frac{5C2\times3C0}{8C2}=\frac{5}{14}
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