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Taya2010 [7]
3 years ago
5

Assume that you select 2 coins at random from 8 coins: 5 dimes and 3 quarters.

Mathematics
1 answer:
Vilka [71]3 years ago
7 0
If the coins are selected without replacement, the probability of 2 dimes is:\frac{5}{8}\times\frac{4}{7}=\frac{5}{14}
The answer is 5/14.
Using the formula for a hypergeometric distribution, we get:
P(2\ dimes)=\frac{5C2\times3C0}{8C2}=\frac{5}{14}
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getting home from trick or treat celia and emma counted their candies. half of celias candies is equal to 2/3 of emmas candies.
blagie [28]

Candies with celias and emmas is 60 and 45 respectively.

<u>Solution:</u>

Given, Getting home from trick or treat celia and emma counted their candies.  Half of celias candies is equal to 2/3 of emmas candies.  

They had a total of 105 candies altogether.  

We have to find how many candies did each of them have.

Let the number of candies with celias be n, then number of candies with emma will be 105 – n.

Now according to given condition.

\begin{array}{l}{\frac{1}{2} \times \text { celias candies count }=\frac{2}{3} \times \text { emmas candies count }} \\\\ {\rightarrow \frac{1}{2} \times n=\frac{2}{3} \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 \times n=2 \times 2 \times(105-n)} \\\\ {\rightarrow 3 n=4(105-n)} \\\\ {\quad \rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n=420-4 n} \\\\ {\rightarrow 3 n+4 n=420} \\\\ {\rightarrow 7 n=7 \times 60} \\\\ {\rightarrow n=60}\end{array}

Hence, candies with celias and emmas is 60 and 45 respectively.

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3 years ago
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g100num [7]

Answer:

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Step-by-step explanation:

the slope-intercept form is y = ax+b

a is the slope, to figure it out the line is perpendicular to y = -5/4x+11/4

There is a rule said if two lines are perpendiculars, the multiplication of their slopes = -1, so -5/4 * a = 1, solve for a = 4/5

b is the intercept to get it use the point (0,7)

so y = 4/5x+b, 7 = 4/5 * 0 + b,  then b = 7

4 0
2 years ago
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