Question

Assume that you select 2 coins at random from 8 coins: 5 dimes and 3 quarters.

Answer 1

If the coins are selected without replacement, the probability of 2 dimes is:$\frac{5}{8}\times\frac{4}{7}=\frac{5}{14}$
The answer is 5/14.
Using the formula for a hypergeometric distribution, we get:
$P(2\ dimes)=\frac{5C2\times3C0}{8C2}=\frac{5}{14}$