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OlgaM077 [116]
3 years ago
12

Mr davis needs 1500 sheets of multicolor paper for students she to make a mural.she has a 5 boxes of multicolor paper. Each box

contains 325 sheets of paper. Could mrs. Davis have used the strategy of halving and doubling to find out if she had enough paper ? Support your answer with information from the problem
Mathematics
2 answers:
baherus [9]3 years ago
4 0
Multiply 325 and 5. Then divide 1500 and that answer! I will let you do the work
Sonbull [250]3 years ago
3 0

Answer:


Step-by-step explanation:


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A baker started out with 12 cups of flour. She had 91/4 cups of flour left after the first batch of batter she made. She had 61/
galben [10]

She would have 1 cup of flour left.  

Work: 6 1/2 - 2 3/4 = 3 3/4 - 2 3/4 = 1


Hope this helps :)

4 0
3 years ago
Read 2 more answers
Can someone please help me or give me the answer only if you know it
Gemiola [76]
It looks like a rectangular prism
volume=W*H*L
6510=w*40*21/2
6510/420=w
w=15.5 feet
8 0
3 years ago
Karen ran 3.5 miles on wednesday and 2.5 miles on thursday. How many feet did she run total?
meriva

Answer:

31,680

Step-by-step explanation:

5 0
3 years ago
Del contenido total de una lata de verduras de 220g,la masa drenada es de 110g. ¡Que fraccion representa la masa drenada del con
saul85 [17]

Explicación paso a paso:

Pregunta 1

El contenido total de verduras = 220 g

La masa drenada es de 110 g.

¿Qué fracción representa la masa drenada del contenido total?

= 110/220

= 22/11

La fracción es 11/22

Pregunta 2

¿Qué fracción decimal corresponde a 1/4?

la fracción decimal que corresponde a 1/4 es 0,25

Pregunta 3

¿Cuánto porcentaje está representado por 1/4 o 0,25?

= 0,25 * 100

= 25%

Pregunta 4

¿Cuánto porcentaje del contenido total representa la masa drenada?

= 110/220 * 100

= 11/22 * 100

= 0,5 * 100

= 50%

7 0
3 years ago
Pls help me.<br>proove it ^​
aivan3 [116]

Answer:

We verified that a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]

Hence proved

Step-by-step explanation:

Given equation is a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]

We have to prove that a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]

That is to prove that LHS=RHS

Now taking RHS

\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]

=\frac{a+b+c}{2}[a^2-2ab+b^2+b^2-2bc+c^2+c^2-2ac+a^2]  (using (a-b)^2=a^2-2ab+b^2)

=\frac{a+b+c}{2}[2a^2-2ab+2b^2-2bc+2c^2-2ac]  (adding the like terms)

=\frac{a+b+c}{2}[2a^2+2b^2+2c^2-2ab-2bc-2ac]

=\frac{a+b+c}{2}\times 2[a^2+b^2+c^2-ab-bc-ac]

=a+b+c[a^2+b^2+c^2-ab-bc-ac]

Now multiply the each term to another each term in the factor

=a^3+ab^2+ac^2-a^2b-abc-a^2c+ba62+b^3+bc^2-ab^2-b^2c-abc+ca^2+cb^2+c^3-abc-bc^2-ac^2]

=a^3+b^3+c^3-3abc (adding the like terms and other terms getting cancelled)

=a^3+b^3+c^3-3abc =LHS

Therefore LHS=RHS

Therefore a^3+b^3+c^3-3abc=\frac{a+b+c}{2}[(a-b)^2+(b-c)^2+(c-a)^2]

Hence proved.

8 0
4 years ago
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