Needs steps to solve the following a^2 + 7ab + 10b^2
1 answer:
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Answer:
(a) Customer will not purchase the light bulbs at significance level of 0.05
(b) Customer will purchase the light bulbs at significance level of 0.01 .
Step-by-step explanation:
We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected, and the following information obtained:
Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.
Let Null hypothesis, :
= 750 {means that the true average lifetime is same as what is advertised}
Alternate Hypothesis, :
< 750 {means that the true average lifetime is smaller than what is advertised}
Now, the test statistics is given by;
T.S. = ~
where, X bar = sample mean = 738.44 hours
s = sample standard deviation = 38.2 hours
n = sample size = 50
So, test statistics = ~
= -2.14
(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.
Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.
(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.
Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.
Answer:
a) 19 students
b) the mean 3 9/19
the median 3
the mode 3
c) the range 6
Step-by-step explanation:
The data set shows that
0 points gets 1 student,
1 point gets 1 student,
2 points get 2 students,
3 points get 6 students,
4 points get 4 students,
5 points get 3 students and
6 points get 2 students.
a) There are 1+1+2+6+4+3+2=19 students.
b) The mean is
The average score is 3 9/19 points.
The median is 10th term in the data set - 3 points (means the middle score in the data set)
The mode is 3 points (means most happened score)
c) The range of the data is 6-0=6 points.