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-BARSIC- [3]
3 years ago
10

Pictures below. Find x.

Mathematics
1 answer:
denis-greek [22]3 years ago
8 0
Hope this helps u...!!

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Sonya took out a mortgage of $65,000 at 7% for 25 years. What is the cost of the mortgage?
Vika [28.1K]

The cost of the mortgage is $81250

<h3>What are interests?</h3>


Interests are percentages of a principal

Given the following parameters

Principal = $65000

Rate = 7% = 0.07
Time = 5 years

<h3>Calculate the interest</h3>

I = PRT/100
I = 65000*0.07*25
I = 16,250

<h3>Determine the cost of the mortgage</h3>

Cost of mortgage = Principal + Interest

Cost of mortgage = 65000 + 16250
Cost of mortgage = 81,250

Hence the cost of the mortgage is $81250

Learn more on mortgage here: brainly.com/question/22846480

5 0
2 years ago
Read 2 more answers
Write each of the following decimals in words.
Sergeeva-Olga [200]

A. nine hundredths

B. Thirty five hundredths

C. Seven Tenths

D. Three Thousandths

E. One Hundred Fourty five Thousandths

F. Fifty Nine Ten Thousandths

8 0
3 years ago
If u help me your dreams will come true ya know
wariber [46]

Answer:

Area of larger circle = \pi *r^2=3.14(11^2)=379.94

Area of smaller circle = \pi *r^2=3.14(3^2)=28.26

Probability that it lands in the shaded area (smaller circle):

28.26 ÷ 379.94 = 0.07438... = 0.07 (nearest hundredth)

8 0
3 years ago
How many milliliters are in 5 liters?
blsea [12.9K]

Answer:

There are 5000 mililitres in 5 litres

Therefore option A.

Hope u got the answer............

5 0
2 years ago
I know you want to answer this question.
Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

\frac{1}{2} ^{x-4} - 3 = 4^{x-3} - 2

First, convert 4^{x-3} to base 2:

4^{x-3} = (2^{2})^{x-3}

\frac{1}{2} ^{x-4} - 3 = (2^{2})^{x-3} - 2

Next, convert \frac{1}{2} ^{x-4} to base 2:

\frac{1}{2} ^{x-4} = (2^{-1})^{x-4}

(2^{-1})^{x-4} - 3 =  (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{-1})^{x-4} = 2^{-1*(x-4)}

2^{-1*(x-4)} - 3 = (2^{2})^{x-3} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

(2^{2})^{x-3} = 2^{2(x-3)}

2^{-1*(x-4)} - 3 = 2^{2(x-3)} - 2

Apply exponent rule: a^{b+c} = a^{b}a^{c}:

2^{-1(x-4)} = 2^{-1x} * 2^{4}, 2^{2(x-3)} = 2^{2x} * 2^{-6}

2^{-1 * x} * 2^{4} - 3 = 2^{2x} * 2^{-6} - 2

Apply exponent rule: (a^{b})^{c} = a^{bc}:

2^{-1x} = (2^{x})^{-1}, 2^{2x} = (2^{x})^{2}

(2^{x})^{-1} * 2^{4} - 3 = (2^{x})^{2} * 2^{-6} - 2

Rewrite the equation with 2^{x} = u:

(u)^{-1} * 2^{4} - 3 = (u)^{2} * 2^{-6} - 2

Solve u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2:

u^{-1} * 2^{4} - 3 = u^{2} * 2^{-6} - 2

Refine:

\frac{16}{u} - 3 = \frac{1}{64}u^{2} - 2

Add 3 to both sides:

\frac{16}{u} - 3 + 3 = \frac{1}{64}u^{2} - 2 + 3

Simplify:

\frac{16}{u} = \frac{1}{64}u^{2} + 1

Multiply by the Least Common Multiplier (64u):

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify:

\frac{16}{u} * 64u = \frac{1}{64}u^{2} + 1 * 64u

Simplify \frac{16}{u} * 64u:

1024

Simplify \frac{1}{64}u^{2} * 64u:

u^{3}

Substitute:

1024 = u^{3} + 64u

Solve for u:

u = 8

Substitute back u = 2^{x}:

8 = 2^{x}

Solve for x:

x = 3

4 0
3 years ago
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