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3 years ago

Which is a correct verbal expression for 9+n

Mathematics

1 answer:

Alex73 [517]3 years ago

8 0

Hello answer is "n is more than 9" !

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12-7(8*9)<br> 82<br>5-82<br>-77<br><img src="https://tex.z-dn.net/?f=12%20-%207%288x9%29%20%3D%20" id="TexFormula1" title="12 -

Goryan [66]

Well, that's incorrect because according to the Order of Operation [GEMS\BOMDAS\PEMDAS etc.], that -7 has to be distributed amongst all the other terms in parentheses. Besides, you did the wrong operation when you inserted that subtraction symbol in substitution of the parentheses, which means to MULTIPLY. So, the order goes as follows:

12 - 7[72]

-504 + 12 = -492 [OR 12 - 504]

-492 is your answer. You get it now?

3 0

3 years ago

The product of a number and ten is twelve more than the product of the number and five-eighths.

ra1l [238]

Let the unknown number be x.

Given,

$10 * x = 12 + \frac{5}{8} * x$

$10x = 12 + \frac{5x}{8}$

$10x - \frac{5x}{8} = 12$

$\frac{(10x*8)-5x}{8} = 12$

$80x-5x =12*8$

$75x = 96$

x = $\frac{96}{75}$ = 1.28

Hence, the number is 1.28

3 0

3 years ago

Velocity is both speed and ___

notka56 [123]

<h3>and health.;</h3><h3 /><h3 /><h3>HOPE THIS HELPED</h3>

6 0

2 years ago

Read 2 more answers

What is the selling price of a $12,543 boat if a $758 discount is given?

Lelu [443]

Given:
Selling Price: 12,543
Discount: 758

We simply deduct the discount from the original price to get the discounted selling price.

12,543 - 758 = 11,785

The new selling price of the boat is $11,785.

Discount of $758 is 6% of the Original selling price.
758 / 12,543 = 0.06
0.06 x 100% = 6%

8 0

3 years ago

Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (

IrinaVladis [17]

Answer:

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14 and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = $\dfrac{9+9}{2}$

median = $\dfrac{18}{2}$

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = $\dfrac{12+13}{2}$

Median = $\dfrac{25}{2}$

Median = 12.5

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = Q3 - Q1

The interquartile range = 12.5 - 9

The interquartile range = 3.5

7 0

3 years ago