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Serhud [2]
3 years ago
15

Given that

ac{2y + x}{x} = 2y" alt=" \frac{2y + x}{x} = 2y" align="absmiddle" class="latex-formula">
then x=​
Mathematics
1 answer:
alexandr1967 [171]3 years ago
8 0

Answer:

Step-by-step explanation:

Hello, please consider the following.

For any x real number different from 0, we can write.

\dfrac{2y + x}{x} = 2y\\\\2y+x=2xy\\\\2xy-x=(2y-1)x=2y\\\\x=\dfrac{2y}{2y-1}

And this is defined for 2y-1 different from 0, meaning y different from 1/2

Thank you.

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A bonsai tree is 18 inches wide and stands 2 feet tall. What is the ration of the width of the bonsai to its height?
Paha777 [63]

Answer:

3:4

Step-by-step explanation:

Before we start to deal with the ratio, we need all lengths in the same units.

The width is 18 inches.

The height is 2 feet.

Let's convert the height to inches. Then we will have both dimensions in the same units, inches.

2 ft * (12 in.)/ft = 24 in.

Now we have:

width = 18 in.

height = 24 in.

ratio of width to height = 18 in. to 24 in. = 18/24 = 3/4 = 3:4

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3 years ago
A town's total allocation for firefighter's wages and benefits in a new budget is $600,000. If wages are calculated at $40,000 pe
tiny-mole [99]
There is 8 firefighters
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2 years ago
Tom begins his morning shift at 9:45
Murrr4er [49]
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6 0
3 years ago
2
Valentin [98]

Answer:

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4 0
3 years ago
Sally launches a rocket off of a platform. The height of the rocket, in meters, can be modeled by the function, h(x) = -5(x - 3)
Lorico [155]

Answer:

Time = 3secs

Max height = 56m

Step-by-step explanation:

Given the height reached by the rocket modeled by the equation;

h(x) = -5(x - 3)² + 56 where;

x is in seconds

The rocket velocity at its maximum height is zero.

Hence dh/dx = 0

dh/dx = 2(-5)(x-3)

dh/dx = -10(x-3)

Since dh/dx = 0

0 = -10(x-3)

0 = -10x + 30

10x = 30

x = 3secs

<em>Hence it takes 3 secs to reach the maximum height.</em>

Get the maximum height reached by the rocket. Substitute x = 3 into the equation given;

Recall that:

h(x) = -5(x - 3)² + 56

If x  = 3

h(3) = -5(3 - 3)² + 56

h(3) = 0 + 56

h(3) = 56

<em>Hence the maximum height that the rocket reaches is 56m</em>

4 0
3 years ago
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