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3 years ago

15

Given that

ac{2y + x}{x} = 2y" alt=" \frac{2y + x}{x} = 2y" align="absmiddle" class="latex-formula">
then x=

1 answer:

alexandr1967 [171]3 years ago

8 0

Answer:

Step-by-step explanation:

Hello, please consider the following.

For any x real number different from 0, we can write.

$\dfrac{2y + x}{x} = 2y\\\\2y+x=2xy\\\\2xy-x=(2y-1)x=2y\\\\x=\dfrac{2y}{2y-1}$

And this is defined for 2y-1 different from 0, meaning y different from 1/2

Thank you.

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What should be added to twice a rational Number -7/3to get 3/7<br>

saul85 [17]

Answer:

107/21

Step-by-step explanation:

re - phrase the question algebraically:

-14/3 + y = 3/7

LCM of 3 and 7 = 21

-98/21 + y = 9/21

what should be added to -98 to make 9?

answer: 107

therefore answer: 107/21

Hope this helps.

Good Luck

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4 years ago

Which sentence best contrasts Greg’s father and Lemon Brown, in "The Treasure of Lemon Brown”? Lemon Brown has shown a deep conc

Vika [28.1K]

Answer:

the correct answer will be B i took the test and got a 100%

Step-by-step explanation:

B. Lemon Brown has lived a more exciting life of a musician, while Greg’s father lives a more stable existence as a postal worker.

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3 years ago

FIND PR.PLS HELP BRAINLIEST...

slega [8]

Answer:

6.2 units.

Step-by-step explanation:

We are given two angles and an opposite corresponding side. To solve for an unknown side, we can use the law of sines.

$\frac{8}{sin(90)}=\frac{x}{sin(180-39-90)}=\frac{x}{sin(51)}$

Cross multiplying and solving will get you this:

$x=\frac{8(sin(51))}{sin(90}$

Which can simplify to:

$x=8(sin(51))$

Which putting into a calculator gets you:

$x=6.2$

So the line PR is 6.2 units long.

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3 years ago

The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g

Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

Step-by-step explanation:

This is a problem of the <em>distribution of sample means</em>. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves <em>normally</em> for samples sizes equal or greater than 30 $\\ n \geq 30$ . Mathematically

$\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$ [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a <em>normal standard distribution</em>, i.e., a normal distribution that has a population mean $\\ \mu = 0$ and a population standard deviation $\\ \sigma = 1$ .

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [2]

From the question, we know that

The population mean is $\\ \mu = 88$ WPM
The population standard deviation is $\\ \sigma = 14$ WPM

We also know the size of the sample for this case: $\\ n = 137$ sixth graders.

We need to estimate the probability that a sample mean being greater than $\\ \overline{X} = 89.87$ WPM in the <em>distribution of sample means</em>. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

$\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}$

$\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}$

$\\ Z = 1.5634 \approx 1.56$

This is a <em>standardized value </em> and it tells us that the sample with mean 89.87 is 1.56<em> standard deviations</em> <em>above</em> the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any <em>cumulative</em> <em>standard normal table</em> available in Statistics books or on the Internet. Of course, this probability is the same that $\\ P(\overline{X} < 89.87)$ . Then

$\\ P(z$

However, we are looking for P(z>1.56), which is the <em>complement probability</em> of the previous probability. Therefore

$\\ P(z>1.56) = 1 - P(z$

$\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594$

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about $\\ P(z>1.56) = 0.0594$ .

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3 years ago

Each side of a square calendar is 19 inches long. What is the calendar's perimeter?

liberstina [14]

Answer:

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3 years ago

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