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DanielleElmas [232]
3 years ago
15

A house was valued at $100,000 in the year 1987. The value appreciated to $165,000 by the year 2002.

Mathematics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

  A) The annual multiplier was 1.0339; the annual increase was 0.0339 of the value.

  B) 3.39% per year

  C) $182,000

Step-by-step explanation:

A) Let's let t represent years since 1987. Then we can fill in the numbers and solve for r.

  165000 = 100000(1 +r)^15

  1.65^(1/15) = 1 +r . . . . . divide by 100,000; take the 15th root

  1.03394855265 -1 = r ≈ 0.0339

The value was multiplied by about 1.0339 each year.

__

B) The value increased by about 3.39% per year.

__

C) S = $100,000(1.03394855265)^18 ≈ $182,000

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Answer:

Step-by-step explanation:

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After that, use sin law to calculate ∠A,

\frac{18.4}{sin90} =\frac{12.8}{sinA}       or    \frac{sin90}{18.4} =\frac{sinA}{12.8}

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A=44.079...

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Is that clear enough for you?

4 0
2 years ago
Help #2-8 please thank you !
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3 years ago
A spherical ball has a diameter of 8 inches. The ball has a slow leak in which the air escapes at the rate of 2.5 inches per sec
s344n2d4d5 [400]

Answer:

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Step-by-step explanation:

Step one:

given

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Step two:

we know that

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4 0
3 years ago
Which of the following is the quotient of b and a?
vlabodo [156]
\bf 19^{\frac{7}{4}}\cdot \sqrt[a]{19^b}=19^{\frac{5}{2}}\sqrt{19}\\\\
-----------------------------\\\\
a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-----------------------------\\\\
thus\qquad 19^{\frac{7}{4}}\cdot 19^{\frac{b}{a}}=19^{\frac{5}{2}}\cdot 19^{\frac{1}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{5}{2}+\frac{1}{2}}
\\\\\\


\bf 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{6}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^3\impliedby 
\begin{array}{llll}
\textit{same base, thus}\\
\textit{exponents must be the same}
\end{array}
\\\\\\
\cfrac{7}{4}+\cfrac{b}{a}=3\implies \cfrac{b}{a}=3-\cfrac{7}{4}
5 0
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