Answer:
Arccos(0.9272) =0.383929333 radian
0.383929333 radian =(0.383929333*57.2957795)degrees
so, 21.99 degrees
Step-by-step explanation:
Rounding to the nearest we get 22 degrees
We know that,
1 radian is equal to 57.2957795
so we multiply the radian value 0.383929333 with it
Answer:
600 pieces
Step-by-step explanation:
pieces/ time(min) = (395-275) / (22-10) = 120/ 12 = 10
10= x (pieces) / 60(min) => x = 60×10 => x = 600 pieces
1m = 100 cm
0.05 m = 5cm
1 km = 10000 cm
0.00005 km = 5 cm
Yes they are equal
(Mark me the brainliest if this has helped!)
Since the given figure is a trapezoid, here is how we are going to find for the value of x. Firstly, the sum of the bases of the trapezoid is always equal to twice of the median. So it would look like this. 2M = A + B.
Plug in the given values above.
2M = (<span>3x+1) + (7x+1)
2(10) = 10x + 2
20 = 10x + 2
20 - 2 = 10x
18 = 10x < divide both sides by 10 and we get,
1.8 = x
Therefore, the value of x in the given trapezoid is 1.8. Hope this is the answer that you are looking for.
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Answer:
Step-by-step explanation:
Hello!
X: Cholesterol level of a woman aged 30-39. (mg/dl)
This variable has an approximately normal distribution with mean μ= 190.14 mg/dl
1. You need to find the corresponding Z-value that corresponds to the top 9.3% of the distribution, i.e. is the value of the standard normal distribution that has above it 0.093 of the distribution and below it is 0.907, symbolically:
P(Z≥z₀)= 0.093
-*or*-
P(Z≤z₀)= 0.907
Since the Z-table shows accumulative probabilities P(Z<Z₁₋α) I'll work with the second expression:
P(Z≤z₀)= 0.907
Now all you have to do is look for the given probability in the body of the table and reach the margins to obtain the corresponding Z value. The first column gives you the integer and first decimal value and the first row gives you the second decimal value:
z₀= 1.323
2.
Using the Z value from 1., the mean Cholesterol level (μ= 190.14 mg/dl) and the Medical guideline that indicates that 9.3% of the women have levels above 240 mg/dl you can clear the standard deviation of the distribution from the Z-formula:
Z= (X- μ)/δ ~N(0;1)
Z= (X- μ)/δ
Z*δ= X- μ
δ=(X- μ)/Z
δ=(240-190.14)/1.323
δ= 37.687 ≅ 37.7 mg/dl
I hope it helps!
