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Nimfa-mama [501]
3 years ago
10

What is the length of the hypotenuse of the triangle?

Mathematics
2 answers:
Inessa [10]3 years ago
6 0

pythagorean theorem

for a right triangle with legs (2 sides next to the the right angle) length a and b, and hyptonuse (longest side oposite right angle) is c

a^2+b^2=c^2


we can see that the legs are 3cm and 7cm

so a=3 and b=7 (you can do a=7 and b=3 but it doesn't matter)

a^2+b^2=c^2

3^2+7^2=c^2

9+49=c^2

58=c^2

sqrare root both sides

\sqrt{58}=c

c=\sqrt{58}

answer is 4th option

Jobisdone [24]3 years ago
3 0

Essentially, we just use the pythagorean theorem to solve:

7^2 + 3^2 = c^2

49 + 9 = c^2

58 = c^2

c = sqrt 58

The answer is Option D.


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Answer:

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Step-by-step explanation:

Given:

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AC^{2}+BD^{2}=BC^{2}+AD^{2}

Solution:

See required figure in attached file.

We know sum of the all angles of a triangle is 180°.

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AD^{2}=AE^{2}+ED^{2}

BC^{2}=BE^{2}+EC^{2}

Now, we add both above equations.

AD^{2}+BC^{2}=AE^{2}+ED^{2}+BE^{2}+EC^{2}--------(1)

Similarly, Using Pythagoras Theorem for triangle AEC and triangle BED.

AC^{2}=AE^{2}+EC^{2}

BD^{2}=BE^{2}+ED^{2}

Now, we add both above equations.

AC^{2}+BD^{2}=AE^{2}+EC^{2}+BE^{2}+ED^{2}--------(2)

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AC^{2}+BD^{2}=BC^{2}+AD^{2}

Hence prove,

AC^{2}+BD^{2}=BC^{2}+AD^{2}

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