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aivan3 [116]
3 years ago
6

Which graph shows the system 1 x² + y = 2 x² + y² = 9

Mathematics
1 answer:
BartSMP [9]3 years ago
5 0

Answer:

The graph of the system in the attached figure

Step-by-step explanation:

we have

x^{2}+y=2

isolate the variable y

y=-x^{2}+2 ----> equation A

This is the equation of a vertical parabola open down (because the leading coefficient is negative)

The vertex represent a maximum

the vertex is the point (0,2)

x^{2} +y^{2}=9 ---> equation B

This is the equation of a circle centered  at (0,0) with radius 3 units

The solution of the system of equations is the intersection points both graphs

using a graphing tool

The solutions are the points (-2.05,-2.19) and (2.05,-2.19)

see the attached figure

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Answer:

[tex]4608\sqrt{3}[/tex]

Step-by-step explanation:

1. \sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}

2. \sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}   <em>factoring 96</em>

<em>since \sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}</em>

3. \sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>using exponent rule - (a^{b}) ^{c} = a^{bc}</em>

<em> \sqrt{2^{5} } = 2^{5/2}</em>

4. 2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>doing some simple simplification and 4=2^{2}  and 6=2*3</em>

5. 2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}

<em>collecting the roots on one side and applying exponent rule</em>

6. \sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}

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3 years ago
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Answer:

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Step-by-step explanation:

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<u><em>The correct answer here is d</em></u>

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2 years ago
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