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Vinvika [58]
3 years ago
5

Your weekly base salary is $150. You earn $20 for each cell phone that you sell. What is the minimum amount you can earn in a we

ek?
Mathematics
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

$150   PLEASE GIVE BRAINLIEST

Step-by-step explanation:

The minimum you can earn would be $150.  This would be your base salary and you selling 0 cell phones.

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(1) One side of a Rhombus measures 13 cm what is its perimeter
Ostrovityanka [42]

Answer:

I want to get point

Step-by-step explanation:

can you help

7 0
3 years ago
Please help!<br> Hard math.
Reil [10]

Answer:

the value of digit 3 in 156.32 =

3 x 0.1 = 0.3


The value of digit 3 in 13 =

3 x 1 = 3

3/0.3=10 times

The value of digit 3 in 13 is 10 ten times the value of digit 3 in 156.32

As long as the (digit in ones/single digit) of a number is equal to 3

The value of digit 3 of it is always 10 ten times the value of digit 3 in 156.32


5 0
3 years ago
Solve each compound inequality (show your work!)
zimovet [89]

Answer:  -1 < x < 8

                x = 3

                x ≠ 2

<u>Step-by-step explanation:</u>

Isolate x in the middle.  Perform operations to all 3 sides.

-6 < 2x - 4 < 12

<u>+4 </u>   <u>      +4</u>   <u>+4 </u>

-2 < 2x       < 16

<u>÷2  </u>  <u>÷2      </u>   <u> ÷2 </u>

-1   <   x       <  8

**************************************************************************

Isolate x.  Solve each inequality separately. Remember to flip the sign when dividing by a negative.

       4x ≤ 12       and       -7x ≤ 21

      <u>÷4  </u>  <u>÷4 </u>                 <u> ÷-7  </u>   <u>÷-7 </u>

        x ≤ 3         and         x ≥  3

Since it is an "and" statement, x is the intersection of both inequalities.

When is x ≤ 3 and ≥ 3?    <em>when x = 3</em>

****************************************************************************

Isolate x.  Solve each inequality separately.

    15x > 30       or           18x < -36

   <u>÷15 </u>  <u> ÷15 </u>                  <u> ÷18  </u>   <u>÷18 </u>

       x > 2          or              x <   2

Since it is an "or" statement, x is the union of both inequalities.

When we combine the inequalities, x is every value except 2.

x ≠ 2

4 0
3 years ago
Ricardo and Tammy practice putting golf balls. Ricardo makes 47% of his putts and Tammy makes 51% of her putts. Suppose that Ric
yaroslaw [1]

Answer:

0.3821 = 38.21% probability that Ricardo makes a higher proportion of putts than Tammy.

Step-by-step explanation:

To solve this question, we need to understand the normal distribution, the central limit theorem, and subtraction of normal variables.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction of normal variables:

When we subtract normal variables, the mean of the subtraction will be the subtraction of the means, while the standard deviation will be the square root of the sum of the variances.

Ricardo makes 47% of his putts, and attempts 25 putts.

By the Central Limit Theorem, we have that:

\mu_R = 0.47, s_R = \sqrt{\frac{0.47*0.53}{25}} = 0.0998

Tammy makes 51% of her putts, and attempts 30 putts.

By the Central Limit Theorem, we have that:

\mu_T = 0.51, s_T = \sqrt{\frac{0.51*0.49}{30}} = 0.0913

What is the probability that Ricardo makes a higher proportion of putts than Tammy?

This is the probability that the subtraction of R by T is larger than 0. The mean and standard deviation of this distribution are, respectively:

\mu = \mu_R - \mu_T = 0.47 - 0.51 = -0.04

s = \sqrt{s_R^2 + s_T^2} = \sqrt{0.0998^2 + 0.0913^2} = 0.1353

This probability is 1 subtracted by the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0 - (-0.04)}{0.1353}

Z = 0.3

Z = 0.3 has a pvalue of 0.6179

1 - 0.6179 = 0.3821

0.3821 = 38.21% probability that Ricardo makes a higher proportion of putts than Tammy.

6 0
3 years ago
Read 2 more answers
The table below represents the displacement of a horse from its barn as a function of time:
taurus [48]

"Part A: What is the y-intercept of the function, and what does this tell you about the horse? (4 points)" The y-intercept is (0,8), which tells us that at the beginning the horse is 8 miles from the barn.


"Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. (4 points)" The value of the function at x=1 is 58 and that at x=3 is 158. Thus, the change in the horse's distance from the barn is 158-58, or 100 feet. The time period involved here is 2 sec. Thus, the average rate of change of the horse's position with respect to time is


100 feet

average rate of change = ---------------- = 50 ft/sec

2 sec


If the horse were to move steadily at a fixed rate from 58 feet to 158 feet from the barn, its average rate would be 50 ft/sec.


"Part C: What would be the domain of the function if the horse continued to walk at this rate until it traveled 508 feet from the barn? (2 points)"


Here time begins at x=0 and ends at x=4 sec. Thus, the appropriate domain here is [0,4] sec.


7 0
3 years ago
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