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3 years ago

This would be a big help so plzzz help me =/

Mathematics

1 answer:

nikdorinn [45]3 years ago

3 0

The correct order would be:

5/64 x 3, 1/16 x 3, 3/32 x 4, 11/64 x 4, 7/16 x 3, 3/4 x 2, 3/8 x 4, 1 7/8 x 4, 2.25 x 2, 1.5 x 4, 3 3/8 x 3, 3.75 x 3

First we have to take all of the numbers and do the multiplication. It's often easiest to turn them in to decimals so that you have a common form.

3/32 x 4 = 3/8 = .375

3/4 x 2 = 3/2 = 1.5

1 7/8 x 4 = 15/4 = 3.75

2.25 x 2 = 4.5

1.5 x 4 = 6

3/8 x 4 = 3/2 = 1.5

5/64 x 3 = 5/32 = .156

3.75 x 3 = 11.25

1/16 x 3 = 3/16 = .1875

7/16 x 3 = 21/16 = 1.31

3 3/8 x 3 = 81/8 = 10.125

11/64 x 4 = 11/16 = .687

Now we can use those to put in order.

5/64 x 3 = 5/32 = .156

1/16 x 3 = 3/16 = .1875

3/32 x 4 = 3/8 = .375

11/64 x 4 = 11/16 = .687

7/16 x 3 = 21/16 = 1.31

3/4 x 2 = 3/2 = 1.5

3/8 x 4 = 3/2 = 1.5

1 7/8 x 4 = 15/4 = 3.75

2.25 x 2 = 4.5

1.5 x 4 = 6

3 3/8 x 3 = 81/8 = 10.125

3.75 x 3 = 11.25

Which if you are looking for without the extra terms, you can check the answer at the top.

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3 years ago

Can you please help. I will give brainleast. Oh and please have an explanation.

Ugo [173]

25/36

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2 years ago

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3 years ago

Verify the identity. cotangent of x divided by quantity one plus cosecant of x equals quantity cosecant of x minus one divided b

Elenna [48]

Answer:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

Step-by-step explanation:

We want to verify the identity:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

Let us take the LHS and simplify to get the LHS.

Express everything in terms of the cosine and sine function.

$\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{1+\frac{1}{\sin x} }$

Collect LCM

$\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{\frac{\sin x+1}{\sin x} }$

We simplify the RHS to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x}{\sin x+1}$

We rationalize to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{(\sin x+1)*(\sin x-1)}$

We expand to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{\sin^2 x-1}$

Factor negative one in the denominator:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-(1-\sin^2 x)}$

Apply the Pythagoras Property to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-\cos^2 x}$

Simplify to get:

$\frac{\cot x}{1+\csc x}=\frac{-(\sin x-1)}{\cos x}$

$\frac{\cot x}{1+\csc x}=\frac{1-\sin x}{\cos x}$

Divide both the numerator and denominator by sin x

$\frac{\cot x}{1+\csc x}=\frac{\frac{1}{\sin x}-\frac{\sin x}{\sin x}}{\frac{\cos x}{\sin x}}$

This finally gives:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

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3 years ago

PLEASE HELP THERE IS A TIMER, I PROMISE A BRAINLIEST TO THE FASTEST CORRECT ANSWER!

morpeh [17]

Answer:

1.25 x 10⁷ km

Step-by-step explanation:

Distance QR = √(3.5 x 10⁶)² + (1.2 x 10⁷)²

= √12.25 x 10¹² + 1.44 x 10¹⁴

= √10¹² (12.25 + 144)

= 10⁶ x 12.5

= 1.25 x 10⁷ km

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3 years ago

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