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slega [8]
3 years ago
14

Please answer correctly !!!! Will mark brainliest !!!!!!!!!

Mathematics
1 answer:
DiKsa [7]3 years ago
6 0
Y = f(x) = 5x - 20 - 6
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On average, a pair of bike tires can last 18 months if used every day. The length of time bike tires can last is exponentially d
aleksandr82 [10.1K]

Answer:

We conclude that eighty percent of bike tires last at most 14.4 months.

Step-by-step explanation:

We know that a pair of bike tires can last 18 months if used every day.

We calculate how much eighty percent of the tire will last in months.

We have the following proportion:

18:100\%=x:80\%\\\\100x=18\cdot 80\\\\100x=1440\\\\x=\frac{1440}{100}\\\\x=14.4

We conclude that eighty percent of bike tires last at most 14.4 months.

5 0
3 years ago
If (-2, y) lies on the graph of y = 4x, then y =<br><br> -16<br> 1/16<br> 16
emmasim [6.3K]
Y = 4x
(-2,y).....x = -2

y = 4(-2)
y = -8
7 0
3 years ago
Read 2 more answers
A construction company wants to hire carpenters for $220 a day and plumbers for $260 a day. The company wants to hire at least 1
joja [24]

Answer:


Step-by-step explanation:

Yes the company can hire 6 carpenters and 12 pumbers

So first lets find out how much it costs to have 6 carpenter for $220 a day.

$220 × 6 = $1320  this is how much it cost to pay 6 carpenters for one day.

Now lets find how much it cost to 12 plumbers at $260 a day.

$260 × 12 = $3120 this is how much it costs to pay 12 plumbers a day.

The total amount you have to pay to the workers is:

$3120 + $1320 = $4440

Your budget was $4500 so the total costs for the workers is $4440 which means you can hire those workers and you would still have $60.


3 0
3 years ago
Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
A wheel in this scale drawing is 4 cm wide. The ratio of the drawing is 1:14. How wide is the actual wheel in cm?
bagirrra123 [75]

1:14 means that for every 1 cm it is drawn at it is actually 14 cm

 so multiply 4 x 14 = 56

 it is actually 56 cm wide

7 0
3 years ago
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