For the given right triangle, the perimeter is 60cm, so the correct option is D.
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How to get the perimeter of the triangle?</h3>
We can see a right triangle, by using the Pythagorean theorem we can get the missing cathetus:


Now we know the measure of the 3 sides, then the perimeter of the given triangle is:
P = 15cm + 20cm + 25cm = 60cm
The perimeter of the triangle is 60cm.
If you want to learn more about right triangles:
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Answer: y=2x+2
Step-by-step explanation:
Rule as an expression: 2x+11-8
Simplify: 2x+2
Rewrite as an equation with x (input) and y (output): y=2x+2
Answer:
So a ratio of 8:3 means for every 8 cars that is 3 trucks so we have the number of trucks which is 21 so what i did to find the answer was see how many times 3 went into 21 which is 7 times then you would take the 7 and times it by 8 and get 56 so there are 56 cars.
Step-by-step explanation:
Answer:
139
Step-by-step explanation:
First we need to find diameter 132/3.14=42 rounded
Then we halve it to find radius 42/2=21
Formula for area is radius x radius x 3.14
21 x 21 = 441 x 3.14 = 138.74 round up is 139
C(x) = 200 - 7x + 0.345x^2
Domain is the set of x-values (i.e. units produced) that are feasible. This is all the positive integer values + 0, in case that you only consider that can produce whole units.
Range is the set of possible results for c(x), i.e. possible costs.
You can derive this from the fact that c(x) is a parabole and you can draw it, for which you can find the vertex of the parabola, the roots, the y-intercept, the shape (it open upwards given that the cofficient of x^2 is positive). Also limit the costs to be positive.
You can substitute some values for x to help you, for example:
x y
0 200
1 200 -7 +0.345 = 193.345
2 200 - 14 + .345 (4) = 187.38
3 200 - 21 + .345(9) = 182.105
4 200 - 28 + .345(16) = 177.52
5 200 - 35 + 0.345(25) = 173.625
6 200 - 42 + 0.345(36) = 170.42
10 200 - 70 + 0.345(100) =164.5
11 200 - 77 + 0.345(121) = 164.745
The functions does not have real roots, then the costs never decrease to 0.
The function starts at c(x) = 200, decreases until the vertex, (x =10, c=164.5) and starts to increase.
Then the range goes to 164.5 to infinity, limited to the solutcion for x = positive integers.