Can you help on this question can you guys please help me?
1 answer:
You might be interested in
Answer:
The partial quotients are 100, 20 and 6. The quotient is 126.
Step-by-step explanation:
The dividend is 378 and the divisor is 3.
First find the factors of 3, near to 300.
The value 300 is less than 378, so record the partial quotient 100 and subtract 300 from 378. Repeat the same process until the dividend has been zero.
Now the remaining divide is 78.
First find the factors of 3, near to 78.
Since 90>78, therefore 30 is not a partial quotient. The value 60 is less than 78 , so record the partial quotient 20 and subtract 60 from 78.
Now the remaining divide is 18.
The number 6 is a partial quotient.
Therefore partial quotients are 100, 20 and 6. Add the partial quotient to find quotient.
This is a problem of Standard Normal distribution.
We have mean= 12 grams
Standard Deviation = 2.5 grams
First we convert 8.5 to z score. 8.5 converted to z score for given mean and standard deviation will be:
So, from standard normal table we need to find the probability of z score to be less than -1.4. The probability comes out to be 0.0808
Thus, the <span>probability that the strawberry weighs less than 8.5 grams is 0.0808</span>
We have mean= 12 grams
Standard Deviation = 2.5 grams
First we convert 8.5 to z score. 8.5 converted to z score for given mean and standard deviation will be:
So, from standard normal table we need to find the probability of z score to be less than -1.4. The probability comes out to be 0.0808
Thus, the <span>probability that the strawberry weighs less than 8.5 grams is 0.0808</span>