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BaLLatris [955]
3 years ago
11

How many three-digit positive integers exist, all of whose digits are 2's and/or 5's?

Mathematics
1 answer:
vfiekz [6]3 years ago
3 0

Answer:

  8

Step-by-step explanation:

There are two choices for each digit, and 3 digits, so 2^3 = 8 possible numbers. Here's a list:

  222, 225, 252, 255

  522, 525, 552, 555

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Step-by-step explanation:

Given

\sqrt{8x^7y^8

Required

Evaluate

\sqrt{8x^7y^8

Separate each factor with multiplication sign

\sqrt{8*x^7*y^8

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\sqrt{4 * 2 *x^6 * x*y^8

Split each factor

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Evaluate \sqrt4

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Apply law of indices:

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Reorder

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2x^3y^4 * \sqrt{2*x}

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