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BaLLatris [955]
4 years ago
11

How many three-digit positive integers exist, all of whose digits are 2's and/or 5's?

Mathematics
1 answer:
vfiekz [6]4 years ago
3 0

Answer:

  8

Step-by-step explanation:

There are two choices for each digit, and 3 digits, so 2^3 = 8 possible numbers. Here's a list:

  222, 225, 252, 255

  522, 525, 552, 555

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If x an integer and 2x +8 <22 and 3x >9, how many possible values of x are there?
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Step-by-step explanation:

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This is further explained below.

<h3>What are the statements?</h3>

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