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Ne4ueva [31]
3 years ago
8

Please help on this question !

Mathematics
1 answer:
netineya [11]3 years ago
5 0
To do this problem hand, you have to start by changing the mixed number into an improper fraction. A handy trick for that is to:
1) Multiply the denominator of the fraction part, 4, by the whole number, 4. So 4*4=16.

2) Add the number in the numerator to the value from step one. So 16+3=19.

3) Put the value from step two over the denominator to get your improper fraction! 19/4

Now you need to multiply to get a common denominator in both values in order to subtract. You have 19/4 - 1/3. This is when you could use a calculator if allowed haha, or multiply 19/4 by 3/3 and 1/3 by 4/4 to get 57/12 - 4/12. Subtract to get 53/12.

Now just do simple division and put the remainer over 12 and simplify the fraction if needed! 53/12 = 4R5. So 4 5/12 is the answer :)
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Quadrilateral ABCD is inscribed in the circle. Which sentence is true?
astra-53 [7]

Answer:

A) A and B are supplementary

Step-by-step explanation:

we know that

For any inscribed  quadrilateral in the circle , opposite angles will be supplementary

so

In this problem

Angle A and Angle B are supplementary angles

m\angle A+m\angle C=180^o

Angle B and Angle D are supplementary angles

m\angle B+m\angle D=180^o

therefore

<u><em>The sentences that are true </em></u>

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3 0
3 years ago
A solid oblique pyramid has a regular hexagon base with an area of 54_/3 cm^2 and an edge length of 6cm. Angle BAC measures 60 d
Lady_Fox [76]

Answer: The answer is (C) 324 cubic cm.


Step-by-step explanation: As given in the question, given a solid oblique pyramid with a regular hexagonal base and area 54√3 cm². Also, the edge length of the base is 6cm and ∠BAC = 60°.

We are to find the volume of the pyramid.

The formula for finding the volume of a pyramid is given by

V=\dfrac{1}{3}b\times h,

where, 'b' is the base area and 'h' is the perpendicular height of the pyramid.

Here, b = 54√3 cm², h = ?

Now, from the right-angled triangle ABC, we have

\dfrac{\textup{BC}}{\textup{AC}}=\tan 60^\circ\\\\\Rightarrow \dfrac{h}{6}=\sqrt 3\\\\\Rightarrow h=6\sqrt 3.

Therefore, the volume of the pyramid is

V=\dfrac{1}{3}b\times h=\dfrac{1}{3}\times 54\sqrt 3\times 6\sqrt 3=324.

Thus, the required volume is V=324~\textup{cm}^3. This makes (C) as the correct option.



5 0
3 years ago
Pls help me with this:((​
BlackZzzverrR [31]

Answer:

9. A. One - to - One Correspondence

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