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3 years ago

Please help on this question !

Mathematics

1 answer:

netineya [11]3 years ago

5 0

To do this problem hand, you have to start by changing the mixed number into an improper fraction. A handy trick for that is to:
1) Multiply the denominator of the fraction part, 4, by the whole number, 4. So 4*4=16.

2) Add the number in the numerator to the value from step one. So 16+3=19.

3) Put the value from step two over the denominator to get your improper fraction! 19/4

Now you need to multiply to get a common denominator in both values in order to subtract. You have 19/4 - 1/3. This is when you could use a calculator if allowed haha, or multiply 19/4 by 3/3 and 1/3 by 4/4 to get 57/12 - 4/12. Subtract to get 53/12.

Now just do simple division and put the remainer over 12 and simplify the fraction if needed! 53/12 = 4R5. So 4 5/12 is the answer :)

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Final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

Step-by-step explanation:

given functions are $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

Now we need to find about what is the value of $g\left(x\right)*f\left(x\right)$ .

$g\left(x\right)*f\left(x\right)$ simply means we need to multiply the value of $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

$g\left(x\right)\cdot f\left(x\right)=\frac{1}{2x\left(x+3\right)}\cdot\left(x-6\right)$

$g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$

Hence final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

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PLEASE HELP ME!!!!!!!!

Delicious77 [7]

Angle θ between two vectors is given by, $\theta =cos^{-1}( \frac{u
 \cdot v}{|u||v|} )$ ; where $u \cdot 
v=-5(-4)+(-4)(-3)=20+12=32$ ; $|u|= \sqrt{ (-5)^{2} + (-4)^{2} } = 
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