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goldenfox [79]
3 years ago
9

Let f(x)=-2x+4 and g(x)=-6x-7 find f(x)-g(x)

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0
f(x)=-2x+4\\ g(x)=-6x-7\\ \\ f(x)-g(x) = -2x+4 - (-6x-7)=-2x+4 +6x+7=4x+11


pav-90 [236]3 years ago
3 0
f(x)-g(x)=-2x+4-(-6x-7)=-2x+4+6x+7=4x+11
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Please find the square roots of the following complex number.
Nana76 [90]

Hey there,

First, find the square root of the given equation.

\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})

Best of Luck!

6 0
2 years ago
I NEED HELP NOW PLS<br><br> PLS THANK YOU PLS
Murrr4er [49]

Answer:

It's C

Step-by-step explanation:

It's C because when you find the least common denominator of 3 and 5 it's 15. So then you convert the fractions to get 6/15+5/15=11/15, which leaves 4/15 left.

4 0
2 years ago
Read 2 more answers
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
What number is 2/10 of 20
I am Lyosha [343]

Answer:

2/10 * 20 = 4.

hope it helps

6 0
2 years ago
Read 2 more answers
pls help me literally pls help me i need this done before tmr ad i have alot more to do pls help thanks
julsineya [31]

Answer:

y = −3x+7

Step-by-step explanation:

m = slope

slope = change in y / change in x

slope = ▲y/▲x

slope = -3 / 1

slope = -3

y-intersect = (0,7)

The slope-intercept form of linear equation:-  

y = mx + b

where:

m = the slope

b = y-intersect

*we plot the information we have get in the formula

y = mx + b

y = -3x + 7

*and this is the equation of the graph

8 0
2 years ago
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