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3 years ago

Help me with this please ❗️❗️❗️❗️❗️❗️

Mathematics

2 answers:

rusak2 [61]3 years ago

7 0

Answer: All the pairs are congruent except A.

Step-by-step explanation:

Congruent line segments are simply segments with the same measure (length).

So, note that in all cases, except for A the measures are identical. The other pairs are all congruent segments.

m_a_m_a [10]3 years ago

3 0

All of them are true except for a

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HELP ASAP I"M JUST TRYING TO GET GOOD GRADES NO LIES EITHER!!

attashe74 [19]

Answer:

C and D

Step-by-step explanation:

If you subtract 2.5 from 16.2 you would get 13.7 same for 19.25.It would then equal 16.75

Therefore C and D are correct :)

6 0

3 years ago

Which of the following is equal to the fraction below?

Talja [164]

Answer:

${( \frac{a}{b}) }^{n} = \frac{ {a}^{n} }{ {b}^{n} } \\ so \\ {( \frac{5}{9} )}^{8} = \frac{ {5}^{8} }{ {9}^{8} }$

4 0

2 years ago

general admission to the fair is 10.00. each ride costs 4.75. if lisa has 75.00 to spend at the fair, what method can be used to

Elis [28]

Answer:

well the answer is 13

Step-by-step explanation:

The way you can figure this out is subtract 10 from 75 to get 65 and then you divide 65 by 4.75 to get 13 with a huge decimal but you just have 13 because you cant go for part of a ride.

PLEASE PUT BRAINLIEST.

6 0

3 years ago

Please Help

Setler79 [48]

19/25 which is likely

count the ones with y and put that over 25

8 0

3 years ago

A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

wel

Answer:

A sample size of 1380 should be obtained.

Step-by-step explanation:

Minimum sample size:

The minimum sample size is of:

$n = (\frac{z}{E})^2(p_1(1-p_1) + p_2(1-p_2))$

In which z is the critical value, related to the confidence level, E is the desired margin of error, $p_1$ and $p_2$ are the proportions.

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

Estimates of 22.6% male and 18.1% female from a previous year

This means that $p_1 = 0.226, p_2 = 0.181$ .

Within 3 percentage points, minimum sample size:

This is n for which $E = 0.03$ . So

$n = (\frac{z}{E})^2(p_1(1-p_1) + p_2(1-p_2))$

$n = (\frac{1.96}{0.03})^2(0.226*0.774 + 0.181*0.819)$

$n = 1379.4$

Rounding up:

A sample size of 1380 should be obtained.

8 0

3 years ago