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Brilliant_brown [7]
3 years ago
10

What digit is in the ten thousands place 1.03098 show how you got this and I will mark brainiest

Mathematics
1 answer:
Luden [163]3 years ago
3 0
The 0 is in the ten thousands
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-14+7-9r+13r someone please helpp !
JulsSmile [24]

Answer:

4r-7

Step-by-step explanation:

-14+7-9r+13r

combine like terms

4r-14+7

combine like terms

4r-7

hope this helped :)

4 0
4 years ago
Read 2 more answers
I got stuck here on this question... this is Algebra 2 btw
svetlana [45]

I don’t think this is algebra 2 but ok

37

I used the formula (32°F − 32) × 5/9 = 0°C (but ofc replaced the numbers with 99)

Yeah and i rounded 98.6 to 99. 99 Fahrenheit is 37.2222... so i rounded it down to 37. So i think the answer is 37.

3 0
3 years ago
What percent of 130 is 182
Greeley [361]
The answer is 140 percent
6 0
4 years ago
This number is 0.02 more than five and five tenths
Nadya [2.5K]
5 and 5/10s sounds like 5.5 so I'd do 5.5+0.02=5.52
6 0
3 years ago
The 3rd term of (a-b)4 is
fgiga [73]

The third term of the expansion is 6a^2b^2

<h3>How to determine the third term of the expansion?</h3>

The binomial term is given as

(a - b)^4

The r-th term of the expansion is calculated using

r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)

So, we have

3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)

Evaluate the sum and the difference

3rd term = C(4, 2) * (a)^2 * (-b)^2

Evaluate the exponents

3rd term = C(4, 2) * a^2b^2

Evaluate the combination expression

3rd term = 6 * a^2b^2

Evaluate the product

3rd term = 6a^2b^2

Hence, the third term of the expansion is 6a^2b^2

Read more about binomial expansion at

brainly.com/question/13602562

#SPJ1

4 0
1 year ago
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