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Vesna [10]
3 years ago
14

Help me with this problem plzzzzzz

Mathematics
1 answer:
Vadim26 [7]3 years ago
5 0

Answer:

B. Opposite angles add up to 180 degrees.

Step-by-step explanation:

Answer Choice B is incorrect because opposite angles are actually congruent. However, adjacent angles of a parallelogram do add up to 180 degrees.

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125 + .375=?<br><br><br> 0.654 + 0.389 - 0.293=?
Lana71 [14]
If it's 125 + 0.375 then the answer is 125.375

and for the second it's 0.75
3 0
3 years ago
Read 2 more answers
Tell which equation you would use to isolate a variable in order to solve the system using substitution. Explain your reasoning.
vampirchik [111]
2x+y=-10
Multiply both side by 3
2x*3+y*3=-10*3
6x+3y=-30

3x-y=0
Multiply both side by 2
3x*2-y*2=0*2
6x-2y=0
Next, use substitute property
6x+3y=-30
    -
6x-2y=0
    =
y=-30
3x-y=0
Substitute y with -30
3x-30=0
Add 30 to each side
3x-30+30=0+30
3x=30
Divided both side by 3
3x/3=30/3
x=10, so the solution pair is (10,-30). In this case, there is the first way to solve these two equation.
Then, I would use equation 3x+1.5y=-15 in this question by multiply 2x+y=-10 by multiplying both side by 3/2 to eliminate x and to solve variables for y. Hope it help!
3 0
4 years ago
If mn = 16 and m^2 + n^2 = 68 then (m+n)^2 =
Dima020 [189]

Answer:

B.   100

Step-by-step explanation:

(m + n)^2

= m^2 + 2mn + n^2

Rearrange

(m^2 + n^2) + 2mn

Substitute

(68) + 2*16

= 68 + 32

= 100

7 0
3 years ago
The fifth grade has 152 students. Each student has 18 pencils. How many pencils do the students have altogether? ( and how did y
timurjin [86]
You're given that there's 152 students. Each student has 18 pencils. All you have to do is multiply 152 students x 18 pencils/student, to get 2,736 pencils.
4 0
4 years ago
You are given g(x)=4x^2 + 2x and
Strike441 [17]

Answer:

324

Step-by-step explanation:

Given:

g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt

Find:

f(6)

First, find f(x):

f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2

Now,

f(6)\\ \\=\dfrac{4\cdot 6^3}{3}+6^2\\ \\=288+36\\ \\=324

4 0
3 years ago
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