What is the equation of the graph below? A graph shows a parabola that opens up with a vertex at negative three comma negative o
1 answer:
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Answer:
y ≈ 2.5
Step-by-step explanation:
Using the Sine rule in Δ XYZ
=
, substitute values
=
( cross- multiply )
y sin50° = 2 sin75° ( divide both sides by sin50° )
y = ≈ 2.5 ( to the nearest tenth )
Consider the attached figure. If AB has length 1, then BC has length sin(15°) and CD (the altitude of triangle ABC) has length sin(15°)·cos(15°).
By the double angle formula for sin(α), ...
... sin(2α) = 2sin(α)cos(α)
Rearranging, this gives
... sin(α)·cos(α) = sin(2α)/2
We have
... CD = sin(15°)·cos(15°) = sin(2·15°)/2
... CD = sin(30°)/2 = (1/2)/2 = 1/4
That is, the altitude, CD, is 1/4 the hypotenuse, AB, of triangle ABC.
Answer:
65°
Step-by-step explanation:
The missing angle is x°
tan x° =
tan x°=
tan x° = 2.125
using a calculator:
- tan^(-1)(2.125) =64.79 ≈65°