Question

What is the equation of the graph below? A graph shows a parabola that opens up with a vertex at negative three comma negative one.

Answer 1

Answer:

$y=(x+3)^2-1\\y=x^2+6x+8$

Step-by-step explanation:

Given:

Vertex of the parabola is, $(h,k)=(-3,-1)$

Equation of the parabola in vertex form is given as:

$y=(x-h)^2+k$

Plug in $h=-3,k=-1$. This gives,

$y=(x-(-3))^2+(-1)\\y=(x+3)^2-1$

Therefore, the equation of the given graph is

$y=(x+3)^2-1\\y=x^2+6x+8$.