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tiny-mole [99]
3 years ago
5

Can someone explain how to do question 3?

Mathematics
1 answer:
konstantin123 [22]3 years ago
5 0
2x^2+2y^2-4x+12y+6=0
you want it in the form
(x-a)^2+(y-b)^2=r^2 where (a,b) is the center and r is the radius hence the name standard center radius form.
dividing by 2 and rearranging
x^2-2x+y^2+6y=-3
by completing the square
x^2-2x+1+y^2+6y+9=-3+9+1
(x-1)^2+(y+3)^2=7
this is the standard radius center form (part b)
to get part a we multipy the equation by 2 to get
2(x-1)^2+2(y+3)^2=14 which is choice (2)
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Find the area of the triangle enclosed by these lines with the following vertices. y = x, x = 0, y = 5 (0,0), (0,5), (5,5)
Lina20 [59]
The are of the triangle will be 12.5 units.

On marking the given vertices (0,0), (0,5), (5,5) of the triangle we get, the base of the triangle = 5 units and height of the triangle = 5 units.

Now, we know area of triangle = \frac{Base * Height}{2} \\ \\ = \frac{5 *5}{2} \\ \\ = \frac{25}{2} \\ \\ = 12.5 units.
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Jobisdone [24]
Slope: -0.8x (means how much the price changes for every year that passes)
y-int: 7.6 (means the price of a ticket when zero years have passed)
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3 years ago
During the 1995 season, Oregon crabbers had a 15 million pound Dungeoness Crab harvest which sold for $24.7 million. That record
fiasKO [112]

Answer:

  36¢ per pound

Step-by-step explanation:

In 1995, the price per pound was ...

  ($24.7 million)/(15 million lb) = $1.6467/lb

In 2000, the price per pound was ...

  ($31,297,583)/(15,616,728 lb) = $2.0041/lb

The difference was ...

  $2.0041 -1.6467 = $0.3574 ≈ 36¢ . . . per pound

_____

In a calculation such as this, you want to keep enough significant digits so that you can appropriately round the final answer. Here, the result would be different if intermediate values were rounded to whole cents.

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What is the slope , m and the y-intercept of the line that is graphed below?
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5 0
4 years ago
Challenge Yael used to have a square garage with 370 ft ^2of floor space. She recently built an
Yuki888 [10]

Scale factor of area is the square of the scale factor of length

The required values are;

  • The length of one sides of the garage was originally approximately <u>19.2 ft.</u>
  • The length of one of the sides of the garage is now approximately <u>23.6 feet</u> long
  • The percentage increase in length is approximately <u>22.5 %</u>

Reason:

The given parameters are;

The area of the square garage = 370 ft.²

The area of the new garage has 50% more space

Required;

Part A

The initial side length

The initial side length, given to the nearest tenth, <em>s</em>, is the square root of the area, <em>A</em>, given as follows;

  • s = √(370 ft.²) ≈ 19.2 ft.

Part B

The side was increased by 50%, to give,

370 + 0.5×370 = 555

The new area of the garage = 555 ft.²

The side length of the new garage, s = √(555) ≈ 23.6

  • The side of the garage now is 23.6 ft.

Part C

The percentage increase is given as follows;

The \ percentage \  increase \ in \ length = \dfrac{New \ length - Initial \ length}{Initial \ length }

The \ percentage \  increase \ in \ length = \dfrac{\sqrt{555}  - \sqrt{370} }{\sqrt{370}  } \times  100 \approx 22.5 \%

  • The percentage increase in length of the side of the garage is approximately 22.5 %

Learn more here:

brainly.com/question/7639412

3 0
3 years ago
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