Answer:
1/6
Step-by-step explanation:
Answer:
2h and 39mins
Step-by-step explanation:
If you are unsure of these times questions. I suggest you draw a timeline! it helps! Trust me!!
Answer:
The vertical line test can be used to determine whether a graph represents a function. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.
Step-by-step explanation:
The vertical line test can be used to determine whether a graph represents a function. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because a function has only one output value for each input value.
I attached an Image you can visualize it clearly
P.S I ain't that good at drawing though :P
The growth of the plant last year was 25 inches if the normal growth was ten inches more than twice the amount of last year.
<h3>What is linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
The normal yearly growth of a plant is 60 inches.
Let's suppose the growth of the plant last year was x
The normal growth was ten inches more than twice the amount of last year.
From the above statement:
10 + 2x = 60
2x = 50
x = 25 inches
Thus, the growth of the plant last year was 25 inches if the normal growth was ten inches more than twice the amount of last year.
Learn more about the linear equation here:
brainly.com/question/11897796
#SPJ1
Answer:
A) 3 in
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Geometry</u>
- Surface Area of a Sphere: SA = 4πr²
- Diameter: d = 2r
Step-by-step explanation:
<u>Step 1: Define</u>
SA = 23 in²
<u>Step 2: Find </u><em><u>r</u></em>
- Substitute [SAS]: 23 in² = 4πr²
- Isolate <em>r </em>term: 23 in²/(4π) = r²
- Isolate <em>r</em>: √[23 in²/(4π)] = r
- Rewrite: r = √[23 in²/(4π)]
- Evaluate: r = 1.35288 in
<u>Step 3: Find </u><em><u>d</u></em>
- Substitute [D]: d = 2(1.35288 in)
- Multiply: d = 2.70576 in
- Round: d ≈ 3 in
