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Andru [333]
3 years ago
15

Bill is picking fruit in his backyard. He picked 5 oranges, 12 apples, and 4 lemons. What percentage of lemons did he pick?

Mathematics
2 answers:
sleet_krkn [62]3 years ago
6 0

Answer:

Step-by-step explanation:

2/5

seraphim [82]3 years ago
4 0

Answer: 0.84

Step-by-step explanation: All of the fruits together is equal to 21 fruits so 4% of 21 is 0.84

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Mathematics fractions to lowest term 34 over 40
bonufazy [111]
34 / 40

2 into 34 is 17, and 2 into 40 is 20.

34 / 20 = 17 / 20

No other number can go into 17 and 20

Answer = 17 / 20  to lowest term.
5 0
3 years ago
If you know the answer to this question please help!! ASAP<br> 7th grade Math
serious [3.7K]

Answer:

22°

Step-by-step explanation:

a right angle have 90°

So

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3 0
4 years ago
A fire hydrant with a blue cap provides water at a rate of 1,500 gallons per minute. A fire hydrant with a green cap provides wa
lapo4ka [179]

Answer:

a) 2b = 3g

b) 3p = b

Step-by-step explanation:

Given:

Fire hydrant with a blue cap, b, provides water at a rate = 1500 gallons per min

Fire hydrant with a green cap, g, provides water at a rate = 1000 gallons per min

Fire hydrant with a purple cap, p, provides water at a rate = ½g = \frac{1}{2}*1000 = 500

a) The equation to relate the flow of water from the blue hydrant, b, to the flow from the green hydrant, g.

Given flow of blue hydrant, b = 500

Simplifying, we have:

b = 3*500

b = 3 * \frac{1000}{2}

Since the flow rate of green hydrant, g, is 1000, let's replace 1000 with g above.

Therefore,

b = 3 * \frac{g}{2}

b = \frac{3}{2}g

Cross multuply

2b = 3g

The equation to relate the flow of water from the blue hydrant, b, to the flow from the green hydrant, g is 2b=3g.

b) An equation to relate the flow of water from the purple hydrant, p, to the flow from the blue hydrant, b.

Given flow rate of purple hydrant, p = 500

It could also be re-written as:

\frac{3}{3} * 500

p = \frac{1500}{3}

Since the flow rate of blue hydrant, b, is 1500, let's replace 1500 with b above.

p = \frac{b}{3}

Cross multiply

3p = b

8 0
3 years ago
At 2:00pm a car's speedometer reads 20mph, and at 2:10pm it reads 30mph.
Dmitry [639]

Over this 10-minute interval, the car's average acceleration is

\dfrac{30\,\mathrm{mph}-20\,\mathrm{mph}}{10\,\mathrm{min}}=\dfrac{10\,\mathrm{mph}}{\frac16\,\mathrm h}=60\dfrac{\rm mi}{\mathrm h^2}

The MVT says that at some point during this 10-minute interval, the car must have had an acceleration of 60 mi/h^2.

6 0
4 years ago
What is the product? 7⋅(−4)⋅(−6) −168 −3 17 168
Lunna [17]

Answer:

The Product of 7⋅(−4)⋅(−6) −168 −3 is<em> </em><u>-3</u>

8 0
3 years ago
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