How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?
Answer: the third option (12 zeros..).
Use ^ to denote an exponent..
f(x) = 3x^12 - 17x^8 + 11x^4 - 6x + 23..
We know from that fact that the number of zeros (real or complex) in a polynomial is the same as the degree of the polynomial..
The degree is the greatest/highest power of the terms, which in this case is 12 (since 12 is the greatest exponent..)..
The degree is 12, thus it means there are 12 zero's..
Answer: the third option (12 zero's )...
Answer:
C i think
Step-by-step explanation:
pls mark brainlyest
Answer:
8t(t - 5)^2
Step-by-step explanation:
I would immediately rearrange these terms in descending order by powers of t:
8t^3 - 80t^2 + 200t
Then I'd factor out 8t:
8t(t^2 - 10 t + 25).
Finally, I'd factor the quadratic t^2 - 10 t + 25:
(t - 5)^2
and so 200t+8t^3-80t^2 in factored form is 8t(t - 5)^2.
