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Maurinko [17]
3 years ago
14

Convert 27/20 to a decimal

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0
27/20

= 20/20 + 7/20

= 1 + 7/20

= 1.00 + 0.35

= 1.35

------

List of values to remember (extras):

0.05 = 1/20 = 5%
0.10 = 1/10 = 10%
0.15 = 3/20 = 15%
0.20 = 1/5 = 20%
0.25 = 1/4 = 25%
0.30 = 3/10 = 30%
0.35 = 7/20 = 35%
0.40 = 2/5 = 40%
0.45 = 9/20 = 45%
0.50 = 1/2 = 50%
0.55 = 11/20 = 55%
0.60 = 3/5 = 60%
0.65 = 13/20 = 65%
0.70 = 7/10 = 70%
0.75 = 3/4 = 75%
0.80 = 4/5 = 80%
0.85 = 17/20 = 85%
0.90 = 9/10 = 90%
0.95 = 19/20 = 95%
1.00 = 1 = 100%
Nikitich [7]3 years ago
8 0
27/20 converted to a decimal is 1.35.
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Answer:

He makes $735.

Step-by-step explanation:

Multiply 22x40 and subtract 145.

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Brady studied 1.5 hours on Monday, 0.75 hours on Tuesday, 1.25 hours on Wednesday, and 1 hour on Thursday. How
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Brady studied for 4.5 hours that week

How we determine the total study hours?

The total study hours for Brady is the sum of the hours used in studying on Monday, Tuesday, Wednesday and Thursday.

He studied for 1.5 hours on Monday

He studied for 0.75 hours on Tuesday

He studied again for 1.25 hours on Wednesday

Lastly, he studied for 1 hour on Thursday, the last day

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8 0
2 years ago
Could you please help me for this question?
Olin [163]

Answer:

  See attached for graphs

  g(x) -- domain: -∞ < x < ∞; range: 0 < y < ∞

  g^-1(x) -- domain: 0 < x < ∞; range: -∞ < y < ∞

Step-by-step explanation:

g(x) is an exponential decay function. Its base is 1/3, so each increase of 1 unit in x will multiply the y-value by a factor of 1/3. The graph will rapidly approach its horizontal asymptote of y=0 as x gets large. The y-intercept is (0, 1). Just as y gets smaller as x increases, so it gets larger as x decreases. Each decrease of x by 1 unit causes the y-value to be multiplied by 3.

__

The graph of g^-1(x) is the graph of g(x) reflected across the line y=x. That is, each coordinate pair (x, y) on the graph of g(x) becomes a point (y, x) on the graph of the inverse function. In order to graph g^-1(x), you don't need to write down the function, you only need to know the relationship between the graphs.

Just as x- and y- are interchanged on the graph, so the domain, range, and intercepts are interchanged. g^-1(x) will have a vertical asymptote of x=0, and an x-intercept of (1, 0). The domain of g^-1(x) is the range of g(x): 0 < x < ∞; and the range of g^-1(x) is the domain of g(x): -∞ < y < ∞.

__

The attached graph shows g(x) in red and g^-1(x) in blue. As you can see, we created the graph simply by interchanging x and y. The line y=x is shown for reference, so you can see that each curve is a reflection of the other across that line.

_____

<em>Additional comment</em>

The explicit expression for g^-1(x) can be found by solving for y:

  x = g(y)

  x=\left(\dfrac{1}{3}\right)^y=\dfrac{1}{3^y}=3^{-y}\\\\ \log(x)=-y\cdot\log(3)\qquad\text{take logarithms}\\\\y=-\dfrac{\log{x}}{\log{3}}=-\log_3{x}\qquad\text{use the change of base relation}\\\\\boxed{g^{-1}(x)=-\log_3{x}}

If you're familiar with the log function, you know it has an x-intercept of 1 and a vertical asymptote at x=0. The base of the log function is simply a vertical scale factor. The minus sign reflects it across the x-axis.

6 0
2 years ago
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