Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
Answer:
Sum of Interior Angles = 900°
One Interior Angle = 128.57°
Step-by-step explanation:
We know that the figure is a Heptagon (a 7 sided polygon), therefore;
→ As by the formula of (n - 2) * 180° we can find the sum of the interior angles;
=> (n - 2) * 180 = Sum of Interior Angles
=> (7 - 2) * 180 = Sum of Interior Angles
=> 5 * 180 = Sum of Interior Angles
=> <u>900° = Sum of Interior Angles</u>
Now that we know the sum of interior angles,
→ We can find 1 interior angle by dividing the sum by the number of sides in the polygon.
=> Sum of Interior Angles / n = One Interior Angle
=> 900 / 7 = One Interior Angle
=> <u>128.57° = One Interior Angle</u>
Hope this helps!
Answer:
The drawing is a little hard to see.
Step-by-step explanation:
Basically you just multiply 2.50 by the other factor.
Answer:
Step-by-step explanation:
(6u)+(-2u)=4u
(-7c)+(4c)=-3c
6=6
4u-3c+6
