The given dimensions of 9.5, 6, 7, and 6.5 cm gives the following
perimeter and area of the trapezium.
<h3>How can the area and perimeter of the trapezium be found?</h3>
The perimeter of a trapezoid is given as follows;
Perimeter = The sum of the lengths of the sides
Which gives;
Perimeter = 6 + 7 + 6.5 + 9.5 = 29
The perimeter of the trapezoid =<u> 29 cm</u>
The area of the trapezoid is given as follows;
![Area = \mathbf{ \dfrac{Sum \ of \ the \ parallel \ sides }{2} \times Height}](https://tex.z-dn.net/?f=Area%20%3D%20%5Cmathbf%7B%20%5Cdfrac%7BSum%20%5C%20of%20%5C%20the%20%5C%20parallel%20%5C%20sides%20%7D%7B2%7D%20%5Ctimes%20Height%7D)
Which gives;
![Area = \dfrac{7 + 9.5 }{2} \times 6 = 49.5](https://tex.z-dn.net/?f=Area%20%3D%20%5Cdfrac%7B7%20%2B%209.5%20%7D%7B2%7D%20%5Ctimes%206%20%3D%2049.5)
The area of the trapezoid = 49.5 cm²
Learn more about the area and perimeter of geometric shapes here:
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Answer:
Prove the lengths are the same
Step-by-step explanation:
When we say segments are congruent, we mean their lengths are the same.
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Let's see if they are congruent.
AD = √((3-(-3))² +(2-2)²) = 6
BC = √((6-0)² +(6-6)²) = 6
AD ≅ BC . . . . their lengths are the same
Answer:
Step-by-step explanation:
Synthetic division is one way to determine whether or not a given number is a root of the quadratic. x^2 − 12x − 20 can be rewritten as x^2 - 12x + 36 - 36 - 20, or (x - 6)^2 - 56, which does not have integer solutions:
(x - 6)^2 - 56 = 0 becomes (x - 6)^2 = 56, which works out to x - 6 = ± 2√14.
None of the possible roots suggested in this problem turns out to be an actual root.
correct response: PRIME