we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx
so
we have
a) for x=1 y=0.50--------> y/x=0.50/1------> 0.50
b) for x=2 y=1--------> y/x=1/2-------> 0.50
c) for x=3 y=1.50--------> y/x=1.50/3-----> 0.50
d) for x=5 y=2.50--------> y/x=2.50/5----> 0.50
the value of k is equal to 0.50
so
<span>the relationship forms a direct variation. </span>
the equation is
y=0.50*x
Verify
for x=1
y=0.50*(1)------> y=0.50-----> is correct
for x=2
y=0.50*(2)------> y=1.00-----> is correct
for x=3
y=0.50*(3)------> y=1.50-----> is correct
for x=5
y=0.50*(5)------> y=2.50-----> is correct
9514 1404 393
Answer:
A. z increased by 8
Step-by-step explanation:
When a positive value is added, the original value (z) is <em>increased</em>.
z + 8 ⇔ z increased by 8
Answer:
28.3
Step-by-step explanation:
Use the Pythagorean Theorem to solve for the answer. 10^2 + x^2 = 30^2
Answer:
40+99
139
Step-by-step explanation:
